我可以从 json 文件创建存根 swagger 模型定义吗 [英] Can I create a stub swagger model definition from a json file

问题描述

是否有工具可以让我从示例 JSON 生成 Swagger yaml 定义模型?

Is there a tool that lets me generate a Swagger yaml definition model from sample JSON?

我会进入并编辑和清理 yaml，但如果有什么东西可以基于大型或复杂的示例 json 对象来剔除 yaml 的结构，那就太好了.

I would go in and and edit and clean up the yaml, but would be nice if there was something out there that would stub out the structure of a yaml based on a large or complex sample json object.

推荐答案

您可以使用具有此功能的 Apigee API Studio:

You can use Apigee's API Studio that has this feature:

http://apistudio.io/

点击插入菜单，然后点击新建模型.形成一个 JSON 示例，您可以创建所需的所有路径和操作.

Click on Insert menu and then New Model. Form a JSON example you can create all of the paths and operations you want.

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