“跳转到定义"对于没有外部参数名称的方法 [英] "Jump to definition" for methods without external parameter names

问题描述

对于带有外部参数名称的方法调用我可以在Xcode中cmd-单击任何参数名称以跳转到方法定义.为了例如，在

For method calls with external parameter names I can cmd-click in Xcode on any parameter name to jump to the method definition. For example, in

let a = Array(count: 3, repeatedValue: 0)  

a cmd-点击count"或repeatedValue"直接跳转到Array初始化方法

a cmd-click on "count" or "repeatedValue" jumps directly to the Array initializer method

init(count: Int, repeatedValue: Element)  

但是，我还没有找到对方法调用执行相同操作的方法没有外部参数名称，如

However, I haven't found a way to do the same for methods calls without external parameter names, as in

let c = Array("abc".characters)

当然我可以查到 characters 方法返回一个 String.CharacterView，它又符合 SequenceType，所以这将调用Array 初始化器

Of course I can lookup that the characters method returns a String.CharacterView which in turn conforms to SequenceType, so this will call the Array initializer

init<S : SequenceType where S.Generator.Element == _Buffer.Element>(_ s: S)  

但我想知道是否有人找到了直接跳转到定义"的方法对于这种情况.

but I wonder if somebody has found a direct "jump to definition" method for this situation.

如果一个类型有许多重载的 init 方法(没有外部参数名称)，这将非常有用，以确定实际调用的是哪个.

This would be very useful if a type has many overloaded init methods (without external parameter names), to determine which one is actually called.

以上例子来自Swift 2/Xcode 7 beta，但问题不在于绑定到一个特殊的 Swift/Xcode 版本.

The above examples are from Swift 2/Xcode 7 beta, but the problem is not tied to a special Swift/Xcode version.

(也在 Apple 开发者论坛上发布:https://forums.developer.apple.com/thread/12687.)

(Also posted at the Apple Developer Forums: https://forums.developer.apple.com/thread/12687.)

推荐答案

你必须做一些工作:

let c = Array.init("abc".characters)
//           ^^^^^

使用 初始化表达式，然后cmd + 点击它.

Use initializer expression, then cmd + click on it.

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