带有 JSON 字典的 POST 请求在 Swift 3 中使用 $_POST 没有返回正确的值? [英] POST Request with JSON dictionary does not return correct value with $_POST in Swift 3?

问题描述

我正在尝试提交要插入数据库的设备 IMEI.

I'm trying to do is submit the device IMEI to be inserted into the database.

但是，从数据库返回的 JSON 输出显示 IMEI 为 null.

However, the returned JSON output from the database shows the IMEI as null.

以下是已实施的内容:

请求者

class Requester
{
    ....

    func postRequest(_ url: URL, headers : Dictionary<String,String>?, data: Data?, callback : @escaping (_ response: HTTPResponseWithData) -> Void) -> Void
    {
        let request = Factory.httpRequest(url, method: "POST", headers: headers, data: data)

        let task = URLSession.shared.dataTask(with: request as URLRequest, completionHandler: {
            data, response, error in

            print("RESPONSE: \(response)");

        })
        task.resume()
    }

    ....
}

工厂

class Factory
{
    func httpRequest(_ url: URL, method: String, headers:     Dictionary<String, String>?, data: Data?) -> URLRequest
    {
        var request = URLRequest(url: url)
        request.httpMethod = method

        if headers != nil
        {
            for (field, value) in headers!
            {
                request.addValue(value, forHTTPHeaderField: field)
            }
        }

        if data != nil
        {
            request.httpBody = data
        }

        return request
    }
}

MainVC

let requester = Requester()

@IBAction func sendRequest(_ sender: Any)
{
    var json: Dictionary<String, Any> = [:]
    json["imei"] = myIMEI

    do
    {
        let data = try JSONSerialization.data(withJSONObject: json, options: .prettyPrinted)

        post(theData: data)
    }
    catch let error as NSError
    {
        print(error.localizedDescription)
    }
}

func post(theData: Data) -> Void
{
    self.requester.postRequest("www.url.com", headers: nil, data: theData, callback: {(response: HTTPResponseWithData) -> Void in

        if response.statusCode == 200 && response.data != nil && HTTPHeader.isContentTypeJSON(response.mimeType)
        {
            print(response.data!)
            do
            {
                if let test = try JSONSerialization.jsonObject(with: response.data!, options: JSONSerialization.ReadingOptions()) as? Dictionary<String, Any>
                {
                    print("test = \(test)")

                 }
            }
            catch
            {
                print("ERROR parsing data")
            }
        }
        else
        {

        }
    });
}

我从输出中得到的是:

test = ["imei": <null>]

我已经查看了许多关于 SO 的问题和答案，除了我在不同的类中的实现之外，我看不出可能有什么问题.

I've looked at numerous questions and answers on SO regarding this, and besides my implementation being in different classes, I don't see what could possibly be wrong.

这是 PHP 代码的一些片段:

Here's some snippet of the PHP code:

header("Content-Type: application/json");

$imei = $_POST["imei"];
$something_else = $_POST["something_else"];

$mysqli = new mysqli($host, $userid, $password, $database);

if ($mysqli->connect_errno)
{
    echo json_encode(array("success" => false, "message" => $mysqli->connect_error, "sqlerrno" => $mysqli->connect_errno));
    exit();
}

echo json_encode( array('imei'=>$imei) );

我的 POST 请求实现到底有什么问题，不允许我将 IMEI 提交到数据库?

What exactly is wrong with my POST request implementation that is not allowing me to submit the IMEI to the database?

如果有帮助，RESPONSE 输出是:

If it helps, the RESPONSE output is:

响应:可选({ URL:http://www.url.com } { 状态码:200，标题{连接 = "保持活动";内容类型"=应用程序/json"；日期 = "2017 年 1 月 2 日星期一 08:07:54 GMT";"Keep-Alive" = "timeout=2, max=96";服务器 = 阿帕奇;传输编码"= 身份；} })

RESPONSE: Optional( { URL: http://www.url.com } { status code: 200, headers { Connection = "Keep-Alive"; "Content-Type" = "application/json"; Date = "Mon, 02 Jan 2017 08:07:54 GMT"; "Keep-Alive" = "timeout=2, max=96"; Server = Apache; "Transfer-Encoding" = Identity; } })

UPDATE: 进一步测试后，我把上面的header后面的php代码换成了下面的代码，现在报了imei:

UPDATE: After further testing, I replaced the above php code after the header with the following code, and now the imei is reported:

$handle = fopen("php://input", "rb");
$raw_post_data = '';

while (!feof($handle))
{
    $raw_post_data .= fread($handle, 8192);
}
fclose($handle);

$request_data = json_decode($raw_post_data, true);
$imei = $request_data["imei"];

我很困惑，为什么更新后的 php 代码有效，而涉及 $_POST 的却没有?

I'm confused, why is it the case that the updated php code works but the one involving $_POST does not?

推荐答案

参见 $_POST 文档 说的是:

See the $_POST documentation which says it is:

使用 application/x-www-form-urlencoded 或 multipart/form 时通过 HTTP POST 方法传递给当前脚本的关联变量数组-data 作为请求中的 HTTP Content-Type.

An associative array of variables passed to the current script via the HTTP POST method when using application/x-www-form-urlencoded or multipart/form-data as the HTTP Content-Type in the request.

但你不是在执行 x-www-form-urlencoded 请求.您正在执行 application/json 请求.所以你不能使用 $_POST.使用 php://input (例如，正如这里所讨论的:iOS 发送 JSON 数据在使用 NSJSONSerialization 的 POST 请求中).

But you're not doing x-www-form-urlencoded request. You're performing an application/json request. So you can't use $_POST. Use php://input (e.g., as discussed here: iOS Send JSON data in POST request using NSJSONSerialization).

这篇关于带有 JSON 字典的 POST 请求在 Swift 3 中使用 $_POST 没有返回正确的值?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！