从数组输入几个数字和整数或不是每一个号检查 [英] Input several numbers from array and each one number check for integer or not
问题描述
大家好!
我希望有人可以帮我找出C语言的东西。
这是我第一次认真的功课在里面,我没有经验,我在电子学研究,所以老师的帮助也不是很用。
我需要开发的C语言控制台应用程序。用户需要输入10整数,如果插入的数目不是整数,需要输出错误并再次重新输入新的号码,直到所有10整数将被插入。
一切正常的情况下,如果我说这10个号码不能为0(我做这是确保我的if-else语句的工作),但我想,每一个输入的数字将支票将无法正常工作如果它是整数或不
我怎么能这样做的权利。
请帮忙
到目前为止,我的code是这样的:
的#include<&stdio.h中GT;
#包括LT&;&stdlib.h中GT;诠释的main()
{
INT I;
浮F;
INT数字[10]; 对于(I = 0; I&小于10;我+ +)
{
scanf函数(%d个,&安培;数字[I]);
如果(数字[I]!= 0)
{
scanf函数(*%D,&安培;数字[I]);
}
其他
{
的printf(!\\ n错误输入的号码岂不等于整数\\ n);
的printf(\\ n请插入数了一遍的\\ n);
scanf函数(%* D,&安培;数字[I]);
} }}
的#include<&stdio.h中GT;诠释主要(无效){
INT I = 0;
INT VAL;
焦炭CH;
INT数字[10]; 而(ⅰ小于10){
VAL = scanf函数(%d个数字+ I); //读取整数为[I]
如果(VAL!= 1){
而((CH =的getchar())!='\\ n')//丢弃无效的输入
; //空声明
的printf(!错误输入的号码不是整数\\ n);
的printf(请重新输入一个整数\\ n);
VAL = scanf函数(%d个数字+ I);
继续;
}
++我;
}
//过程的数字阵列
返回0;
}
我再次写这行
VAL = scanf函数(%d个数字+ I);
现在它的工作原理我怎么需要。伟大的 - 非常感谢
everyone! I hope someone can help me figure out something in C language. This is my first seriously homework in IT, I have no experience and I'm learning in e-studies, so teacher help isn't very available.
I need to develop console application in C language. User need to input 10 integer numbers, if insert number isn't integer, need to output error and again re-enter new number until all 10 integer numbers will be inserted.
Everything works in case if I say that these 10 numbers can't be 0 (I make this to be sure that my if-else statement working), but won't work when I want that every input number will be check if it is integer or not.
How can I do it right.
Please help
so far my code look like this:
#include <stdio.h>
#include <stdlib.h>
int main()
{
int i;
float f;
int numbers[10];
for (i = 0; i < 10; i++)
{
scanf ("%d", &numbers[i]);
if (numbers[i] != 0)
{
scanf ("*%d", &numbers[i]);
}
else
{
printf ("\nError!Entered number is't integer \n");
printf ("\nPlease insert number again \n");
scanf("%*d", &numbers[i]);
}
}
}
#include <stdio.h>
int main(void) {
int i = 0;
int val;
char ch;
int numbers[10];
while(i < 10) {
val = scanf("%d", numbers + i); // read the integer into a[i]
if(val != 1) {
while((ch = getchar()) != '\n') // discard the invalid input
; // the null statement
printf("Error! Entered number is not an integer.\n");
printf("Please enter an integer again.\n");
val = scanf("%d", numbers + i);
continue;
}
++i;
}
// process the numbers array
return 0;
}
I write this line again
val = scanf("%d", numbers + i);
Now it works how I need. Great - thanks a lot
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