SwiftUI 中的可选 @ObservableObject [英] Optional @ObservableObject in SwiftUI

查看:27
本文介绍了SwiftUI 中的可选 @ObservableObject的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想在 SwiftUI 中有一个可选的 @ObservedObject,但我一直收到编译时错误.

I want to have an optional @ObservedObject in SwiftUI but I keep getting a compile time error of.

Property type 'AModel?' does not match that of the 'wrappedValue' property of its wrapper type 'ObservedObject'

这是一些最低限度的可重现代码.

Here is some minimum reproducible code.

import SwiftUI

public struct AView: View {
    
    //MARK: View Model
    //Error thrown here.
    @ObservedObject var model: AModel?
    
    //MARK: Body
    public var body: some View {
        Text("\(model?.value ?? 0)")
    }
    
    //MARK: Init
    public init() {
        
    }
    
}

class AModel: ObservableObject {
    let value: Int = 0
}

推荐答案

技术原因是 Optional 不是一个类,所以不能符合 ObservableObject.

The technical reason is that Optional is not a class, so it cannot be conformed to ObservableObject.

但是如果你想避免重构对象本身——例如,如果它不在你的控制范围内——你可以这样做:

But if you want to avoid refactoring the object itself - for example, if it's not in your control - you could do something like this:

struct AView: View {

    private struct Content: View {
       @ObservedObject var model: AModel
       var body: some View {
          Text("\(model.value)")
       }
    }

    var model: AModel?
    
    var body: some View {
       if let model = model {
          Content(model: model)
       } else {
          Text("0")
       }
    }    
}

这篇关于SwiftUI 中的可选 @ObservableObject的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆