如何使用 SwiftyJSON 在 Json 中解析 Json? [英] How Can I Parse Json In Json With SwiftyJSON?
问题描述
我从 API 返回以下 JSON.在我的数据库中,我已经在 JSON 中存储了一个列表.因此,它在 JSON 中为我们提供了一个 JSON 字符串.如何在 Swift 中将这些作为对象访问?更重要的是:如何在 JSON 中解析 JSON?
I am returning the following JSON from an API. In my database, I store a list in JSON already. Thus, it gives us a string of JSON inside JSON. How can I access these as objects in Swift? More to the point: How can I parse JSON inside of JSON?
{
"checklists": [
{
"id": 1,
"account_id": 15,
"user_id": 15,
"object_id": 21,
"checklist": "[{\"title\":\"Test\",\"summary\":\"Test 12\"},{\"title\":\"Test 2 \",\"summary\":\"Test 123\"}]",
"title": "High Altitude Operations",
"type": "other",
"LastHistory": null,
"CleanArray": [
{
"title": "Test",
"summary": "Test 12"
},
{
"title": "Test 2 ",
"summary": "Test 123"
}
]
}
]
}
推荐答案
首先解码主对象.
假设 data
是您问题中的 JSON:
Let's say data
is the JSON in your question:
let json = JSON(data: data)
要获取checklists
键内数组中checklist
键的内容,我们可以像这样使用SwiftyJSON的键路径下标:
To get the content of the checklist
key inside the array inside the checklists
key, we can use SwiftyJSON's key path subscripting like this:
let checkList = json["checklists",0,"checklist"]
print(checkList)
打印:
[{"title":"Test","summary":"Test 12"},{"title":"Test 2","summary":"Test 123"}]
[{"title":"Test","summary":"Test 12"},{"title":"Test 2 ","summary":"Test 123"}]
这是作为字符串的内部 JSON.
This is your inner JSON as a String.
将其设为数据,然后执行相同的过程并访问数组内容:
Make it data, then do the same process and access the array content:
if let json2String = checkList.string,
data2 = json2String.dataUsingEncoding(NSUTF8StringEncoding) {
let json2 = JSON(data: data2)
let checkList2 = json2[0]
let title = checkList2["title"]
print(title)
}
打印:
测试
请注意,我在此示例中使用了键路径下标,但简单下标、循环和 map/flatMap/etc 等常用技术也可以使用:
Note that I've used key path subscripting for this example, but usual techniques like simple subscripting, loops and map/flatMap/etc also work:
let mainChecklists = json["checklists"]
for (_, content) in mainChecklists {
if let innerString = content["checklist"].string,
data2 = innerString.dataUsingEncoding(NSUTF8StringEncoding) {
let json2 = JSON(data: data2)
for (_, innerChecklist) in json2 {
let title = innerChecklist["title"]
print(title)
}
}
}
打印:
测试
测试 2
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