symfony2 存储上传的文件非 rootweb [英] symfony2 store uploaded file non rootweb

问题描述

我上传文件时遇到问题，我将上传的文件保存在非公共文件夹(非 webroot 文件夹)中，然后我想获取所有上传文件的 webPAth 以在视频库中使用它们.

I have problem with uploading files, I'm saving uploaded files in a non public folder (non webroot folder), and then I want to get the webPAth of all uploaded files to use them in a video gallery.

$videos = $repository->getVideosThumbs($this->getUser());

然后在我的树枝上

{% for video in videos %}
         <a href ="{{ path('neoctus_videobundle_default_watchvideo', {'id' : video.id, 'salt' : app.user.salt }) }}" >
            <img id="{{ video.id }}" src="/uploads/images/{{video.imgPath}}" alt="1st image description" height="150" width="150"  />
         </a>
    {% endfor %}

但是我无法访问图片，因为该文件夹不是公开的，我知道我必须通过 x-sendFile 但我不知道如何在标题中发送多个 jpeg 文件，然后如何在树枝后恢复.

but I can not access the pictures because the folder is not public, I know I have to go through x-sendFile but I do not see how I can send multiple jpeg files in the header and then how recover after the twig.

推荐答案

您可以创建控制器操作来访问存储在非公共文件夹中的文件.在该操作中，您打开文件并流式传输到浏览器.

You could create a controller action to access files that are stored in a non public folder. In that action, you open file and stream in to browser.

参见 http://php.net/manual/en/function.readfile 中的示例.php

你需要改变

header('Content-Disposition: attachment; filename='.basename($file));

到

header('Content-Disposition: inline; filename='.basename($file));

更新:

当您拥有可以流式传输请求文件的控制器操作时，您可以通过使用所需的文件标识符请求该操作来在您的 TWIG 中呈现它:

When you have your controller action that would stream requested file, you can render it in your TWIG by requesting that action with required file identifier:

<img src="{{ path('route_to_stream_action', {'fileId':'some_id'}) }}">

浏览器会像对待直接访问一样对待流式文件，因此您可以对其应用任何 CSS.

Browser will treat streamed file the same way as if it was accessed directly, so you can apply any CSS to it.

更新:

示例控制器操作:

public function streamFileAction($fileId)
{

    // implement your own logic to retrieve file using $fileId
    $file = $this->getFile($fileId);

    $filename = basename($file);

    $response = new StreamedResponse();
    $response->setCallback(function () use ($file){
        $handle = fopen($file->getRealPath(), 'rb');
        while (!feof($handle)) {
            $buffer = fread($handle, 1024);
            echo $buffer;
            flush();
        }
        fclose($handle);
    });
    $d = $response->headers->makeDisposition(ResponseHeaderBag::DISPOSITION_INLINE, $filename);
    $response->headers->set('Content-Disposition', $d);
    $response->headers->set('Content-Type', $file->getMimeType());

    return $response;
}

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