将自定义参数传递给 Symfony2 中的自定义 ValidationConstraint [英] Pass custom parameters to custom ValidationConstraint in Symfony2
问题描述
我正在 Symfony2 中创建一个表单.该表单仅包含一个 book
字段,允许用户在 Books
实体列表之间进行选择.我需要检查所选的 Book
是否属于我的控制器中的 Author
.
I'm creating a form in Symfony2. The form only contains one book
field which allows the user to choose between a list of Books
entities. I need to check whether the selected Book
belongs to an Author
I have in my controller.
public class MyFormType extends AbstractType
{
protected $author;
public function __construct(Author $author) {
$this->author = $author;
}
public function buildForm(FormBuilderInterface $builder, array $options) {
$builder->add('book', 'entity', array('class' => 'AcmeDemoBundle:Book', 'field' => 'title');
}
// ...
}
我想在提交表单后检查所选的 Book
是否由我的控制器中的 $author
编写:
I want to check, after submitting the form, that the selected Book
is written by the $author
in my controller:
public class MyController
{
public function doStuffAction() {
$author = ...;
$form = $this->createForm(new MyFormType($author));
$form->bind($this->getRequest());
// ...
}
}
不幸的是,我找不到任何方法来做到这一点.我尝试按照 The Cookbook 中的说明创建自定义验证器约束,但是虽然我可以通过将验证器定义为服务来将 EntityManager
作为参数传递,我不能将 $author
从控制器传递给验证器约束.
Unfortunately, I cannot find any way to do that. I tried creating a custom validator constraint as explained in The Cookbook, but while I can pass the EntityManager
as parameter by defining the validator as a service, I cannot pass the $author
from the controller to the validator constraint.
class HasValidAuthorConstraintValidator extends ConstraintValidator
{
private $entityManager;
public function __construct(EntityManager $entityManager) {
$this->entityManager = $entityManager;
}
public function validate($value, Constraint $constraint) {
$book = $this->entityManager->getRepository('book')->findOneById($value);
$author = ...; // That's the data I'm missing
if(!$book->belongsTo($author))
{
$this->context->addViolation(...);
}
}
}
这个解决方案可能就是这样我一直在寻找,但我的表单没有绑定到实体,也不意味着(我从 getData()
方法获取数据).
This solution could be exactly the one that I was looking for, but my form is not bound to an Entity and is not meant to be (I'm getting the data from the getData()
method).
我的问题有解决方案吗?这一定是个常见的情况,但我真的不知道如何解决.
Is there a solution to my problem ? This must be a common case but I really don't know how to solve it.
推荐答案
在 Cerad 的帮助下,我终于弄明白了.要注入需要从 ConstraintValidator::validate()
方法访问的自定义参数,您需要在 Constraint
中将它们作为 options 传递.
I finally figured it out, with the help from Cerad. To inject custom parameters that need to be accessed from the ConstraintValidator::validate()
method, you need to pass them as options in the Constraint
.
public class HasValidAuthorConstraint extends Constraint
{
protected $author;
public function __construct($options)
{
if($options['author'] and $options['author'] instanceof Author)
{
$this->author = $options['author'];
}
else
{
throw new MissingOptionException("...");
}
}
public function getAuthor()
{
return $this->author;
}
}
并且,在 ConstraintValidator 中:
And, in the ConstraintValidator:
class HasValidAuthorConstraintValidator extends ConstraintValidator
{
private $entityManager;
public function __construct(EntityManager $entityManager) {
$this->entityManager = $entityManager;
}
public function validate($value, Constraint $constraint) {
$book = $this->entityManager->getRepository('book')->findOneById($value);
$author = $this->constraint->getAuthor();
if(!$book->isAuthor($author))
{
$this->context->addViolation(...);
}
}
}
最后但并非最不重要的是,您必须将参数传递给验证器:
Last but not least, you have to pass the parameter to the Validator:
public function buildForm(FormBuilderInterface $builder, array $options) {
$builder->add('book', 'entity', array(
'class' => 'AcmeDemoBundle:Book',
'field' => 'title',
'constraints' => array(
new HasValidAuthorConstraint(array(
'author' => $this->author
))
)
));
}
这篇关于将自定义参数传递给 Symfony2 中的自定义 ValidationConstraint的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!