从自定义身份验证处理程序调用默认处理程序 [英] Calling default handler from a custom authentication handler

问题描述

可能的重复:
Symfony2 AJAX 登录

我已经实现了一个自定义身份验证处理程序服务来处理 AJAX 登录请求，如下所示:https://stackoverflow.com/a/8312188/267705

I have implemented a custom authentication handler service to handle AJAX login requests, as suggested here: https://stackoverflow.com/a/8312188/267705

但是我如何处理正常的登录请求?调用默认行为会很好，但我不知道也没有找到如何去做.

But how can I handle normal login requests? It would be nice to call the default behavior, but I don't know and haven't found how to do it.

推荐答案

这是实现您想要的方法之一:

This is one of the ways to achieve what you want:

namespace YourVendor\UserBundle\Handler;

// "use" statements here

class AuthenticationHandler
implements AuthenticationSuccessHandlerInterface,
           AuthenticationFailureHandlerInterface
{
    private $router;

    public function __construct(Router $router)
    {
        $this->router = $router;
    }

    public function onAuthenticationSuccess(Request $request, TokenInterface $token)
    {
        if ($request->isXmlHttpRequest()) {
            // Handle XHR here
        } else {
            // If the user tried to access a protected resource and was forces to login
            // redirect him back to that resource
            if ($targetPath = $request->getSession()->get('_security.target_path')) {
                $url = $targetPath;
            } else {
                // Otherwise, redirect him to wherever you want
                $url = $this->router->generate('user_view', array(
                    'nickname' => $token->getUser()->getNickname()
                ));
            }

            return new RedirectResponse($url);
        }
    }

    public function onAuthenticationFailure(Request $request, AuthenticationException $exception)
    {
        if ($request->isXmlHttpRequest()) {
            // Handle XHR here
        } else {
            // Create a flash message with the authentication error message
            $request->getSession()->setFlash('error', $exception->getMessage());
            $url = $this->router->generate('user_login');

            return new RedirectResponse($url);
        }
    }
}

享受.;)

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