如何在 Symfony 2 的类中获取 Request 对象? [英] How can I get Request object inside a class in Symfony 2?

问题描述

我在 Symfony 中有一个实现接口的类.我需要有 $request 才能有 POST 参数.这是我的功能:

I have a class in Symfony that implements an interface. I need to have $request to have POST params. This is my function:

class WebserviceUserProvider implements UserProviderInterface
{
    public function loadUserByUsername($username)
    {
        $salt = "";
        $roles = "";
        // make a call to your webservice here

        .....
    }
...
}

我不能这样做:

public function loadUserByUsername($username, Request $request)

因为我需要实现接口，我得到这个错误:

because i need to implement the interface, and i get this error:

FatalErrorException:编译错误:声明Actas\Gestion\UserBundle\Security\User\WebserviceUserProvider::loadUserByUsername()必须兼容Symfony\Component\Security\Core\User\UserProviderInterface::loadUserByUsername($username)

FatalErrorException: Compile Error: Declaration of Actas\Gestion\UserBundle\Security\User\WebserviceUserProvider::loadUserByUsername() must be compatible with Symfony\Component\Security\Core\User\UserProviderInterface::loadUserByUsername($username)

如何获取请求参数?这个类是从登录调用的，我需要它发送的密码才能使用 WebService 对用户进行身份验证.

How can i get the request params? This class is called from login, and i need the password sent by it to use a WebService to authenticate the user.

在此先非常感谢您！

这是我在 Bundle 中的 services.xml:

This is my services.xml in the Bundle:

# src/Actas/Gestion/UserBundle/Resources/config/services.yml
parameters:
    webservice_user_provider.class: Actas\Gestion\UserBundle\Security\User\WebserviceUserProvider

services:
    webservice_user_provider:
        class: "%webservice_user_provider.class%"
        scope: container
        calls:
                - [setServiceContainer , ["@service_container"]]

推荐答案

除了 Czechnology 的回答，您还可以使用 setter 方法注入请求.在 services.yml 添加:

In addition to Czechnology's answer, you could also inject the request using a setter method. In services.yml add:

my_service:
    class: Acme\DemoBundle\Service\WebserviceUserProvider
    scope: request
    calls:
        - [setRequest , ["@request"]]

然后像这样声明你的类:

Then declare your class like this:

use Symfony\Component\HttpFoundation\Request;

class WebserviceUserProvider implements UserProviderInterface {
    private $request;
    public function setRequest( Request $request ) {

        $this->request = $request;
    }
    // ...
}

如果您遇到范围扩大问题，您还可以尝试注入服务容器并从中获取请求.在服务中像这样声明你的服务:

If you have scope widening issues, you could also try injecting the service container and getting the requesting from it. In services declare your service like this:

my_service:
class: Acme\DemoBundle\Service\WebserviceUserProvider
calls:
    - [setRequest , ["@service_container"]]

现在只需使用容器来获取请求:

Now just use the container to get the request:

use Symfony\Component\DependencyInjection\ContainerInterface;
use Symfony\Component\HttpFoundation\Request;

class WebserviceUserProvider implements UserProviderInterface {
    private $request;
    public function setRequest( ContainerInterface $container ) {

        $this->request = $container->get('request');
    }
    // ...
}

这篇关于如何在 Symfony 2 的类中获取 Request 对象?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！