Symfony2 显式获取 URL 的路径信息 [英] Symfony2 get path info of URL explicitely
问题描述
比如说,我有一个 URL http://server/mysite/web/app_dev.php/resource/1
.我正在执行一个 GET
请求,相应的操作是 ResourceController::getAction
.
Say, I have an URL http://server/mysite/web/app_dev.php/resource/1
.
I am doing a GET
request and the corresponding action is ResourceController::getAction
.
在这个控制器动作中,如果我调用 $request->getPathInfo()
,它会给我 /resource/1
.
In this controller action if I call $request->getPathInfo()
, it gives me /resource/1
.
但是在同一个控制器中,如果我使用另一个资源的 url 创建一个 Request 对象并调用 getPathInfo()
它返回一个更长的版本.
But in the same controller if I create a Request object with a url of another resource and call getPathInfo()
it returns a longer version.
$request = Request::create('http://server/mysite/web/app_dev.php/another_resource/1');
echo $request->getPathInfo();
OUTPUT >>
/mysite/web/app_dev.php/another_resource/1
在这种情况下,如何让 getPathInfo()
只返回 /another_resource/1
?
How is it possible to make getPathInfo()
to return only /another_resource/1
in this case?
任何人都可以建议将端点 URL http://server/mysite/web/app_dev.php/another_resource/1
转换为 /another_resource/1
的最安全方法是什么代码>在Symfony2中?
Anyone can suggest what is the safest way to convert an endpoint URL http://server/mysite/web/app_dev.php/another_resource/1
to /another_resource/1
in Symfony2?
控制器操作正在接收请求内容中的一些 URL.该操作需要解析这些 URL 以识别相应的资源.我正在尝试使用 $router->match
函数从 URL 中检索参数.匹配函数只需要 /another_resource/1
部分.
The controller action is receiving some URLs in request content. The action needs to parse those URLs to recognize the corresponding resource. I am trying to make use to $router->match
function to retrieve the parameters from the URL. The match function expects only /another_resource/1
part.
推荐答案
Request::create 方法创建一个不知道当前请求的任何信息的新请求,它返回完整的 uri,因为它不知道当前的脚本文件.试试:
Request::create method create a new request that don't know any information about current request, it return full uri because it not know current script file. try:
$request = Request::create('http://server/mysite/web/app_dev.php/another_resource/1', null, array(), array(), array(), array(
'SCRIPT_NAME' => $this->get('kernel')->getEnvironment() == 'dev' ? 'app_dev.php' : 'app.php',
'SCRIPT_FILENAME' => $this->get('kernel')->getEnvironment() == 'dev' ? 'app_dev.php' : 'app.php',
));
echo $request->getPathInfo();
这篇关于Symfony2 显式获取 URL 的路径信息的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!