是否有等价于 Mathematica 的“用法"?功能? [英] Is there an equivalent to Mathematica's "usage" function?

问题描述

在数学中，可以定义一个函数的标签，例如

In Mathematicy, one can define tags of a function such as

f::usage = "f[x] gives (x - 1)(x + 1)";

然后可以这样调用:

?f

SymPy 中是否有等价物?

Is there an equivalent in SymPy?

推荐答案

您可以猴子补丁"文档字符串如下:

You can "monkey patch" the docstring as follows:

import sympy
f = sympy.Function("f")
f.__doc__ = "A naked function without any special properties"

您可以以相同的方式检索文档字符串，例如 print(f.__doc__).在 iPython 和类似的情况下，您也可以使用 f? 来获取它(连同一些其他信息).

You can retrieve the docstring in the very same way, e.g., print(f.__doc__). In iPython and similar, you can also use f? to obtain it (together with some other information).

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