解析错误:语法错误，第 128 行文件中意外的 $end [英] Parse error: syntax error, unexpected $end in file on line 128

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问题描述

这是代码:它是一个页面，用于在下拉列表中显示我在数据库中可用的表，然后在表中显示结果.这样做的实际代码(在中间)可以完美地工作，但是当我尝试在它周围添加我的模板时，我得到了错误......

<html xmlns="http://www.w3.org/1999/xhtml"><头><meta name="keywords" content="" ><meta name="description" content="" ><meta http-equiv="content-type" content="text/html; charset=utf-8" ><title>SNYSB 档案</title><link href="style.css" rel="stylesheet" type="text/css" media="screen" ><!-- javascript 的位置.--><script language="javascript" type="text/javascript" src="swfobject.js" ></script><div id="包装器"><div id="标题"><!-- 保留这个位[它的格式]-->

<!-- 结束 #header --><div id="菜单"><ul><li><a href="Hpage.php">首页</a></li><li><a href="Register.php">注册</a></li>

<!-- 结束#menu --><div id="页面"><div id="page-bgtop"><div id="page-bgbtm"><div id="内容"><div class="post"><div class="post-bgtop"><div class="post-bgbtm"><h1 class="title">把标题放在这里！</h1><div class="entry"><p class="Body"><?php$dbname = 'snysbararchive';$conn= mysql_connect('localhost', 'root', 'usbw');如果(！$conn){echo '无法连接到mysql';出口;}$sql = "从 $dbname 显示表";$result = mysql_query($sql);如果(！$结果){echo "数据库错误，无法列出表\n";echo 'MySQL 错误:'.mysql_error();出口;}如果 (mysql_select_db($dbname, $conn)){?><form method="post" action="new 2.php"><选择名称=表格"><?phpwhile ($row = mysql_fetch_row($result)) {?><?phpecho '<option value="'.$row[0].'">'.$row[0].'</option>';}?></选择><输入类型=提交"值=显示"></表单><?php//mysql_free_result($result);if (isset($_POST) &&isset($_POST['tables'])){$tbl=$_POST['tables'];//echo $_POST['tables']."<br/>";$query="SELECT * from $tbl";$res=mysql_query($query);回声 $query;如果($res){?><表格边框=1"><?phpwhile ( $row = mysql_fetch_array($res)){echo "";echo "<td>".$row[0]."</td>";echo "<td>".$row[1]."</td>";echo "<td>".$row[2]."</td>";echo "<td>".$row[3]."</td>";回声</tr>";?><?php}}?>

<div style="clear: both;">&nbsp;</div>

<!-- 结束#content --><div id="侧边栏"><ul><li><h2>欢迎！</h2><p>欢迎来到 SNYSB 档案！</p><li><h2>SNYSB</h2><p><a href="Contact.php">联系我们！</a></p>

<!-- end #sidebar --><div style="clear: both;">&nbsp;</div>

<!-- 结束#page --><div id="页脚"><p>版权所有 (c) 2008 Sitename.com.版权所有.由<a href="http://www.freecsstemplates.org/">免费 CSS 模板</a>设计.</p>

<!-- 结束 #footer -->

</html>

它一直说意外结束，但我不知道如何解决?

错误信息:解析错误:语法错误，第 128 行的文件中出现意外的 $end

谢谢

解决方案

您没有选择您的数据库并在函数周围使用正确的大括号.

Hi So this is the code: Its a page to display my available tables in the database in a drop-down, then display the results in the table. The actual code to do so (in the middle) works perfectly on its own, but when I try to add my template around it I get errors...

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta name="keywords" content="" >
<meta name="description" content="" >
<meta http-equiv="content-type" content="text/html; charset=utf-8" >
<title>SNYSB Archive</title>
<link href="style.css" rel="stylesheet" type="text/css" media="screen" >
<!-- Location of javascript. -->
<script language="javascript" type="text/javascript" src="swfobject.js" ></script>
</head>
    <div id="wrapper">
    <div id="header">
    <!-- KEEP THIS BIT [ITS FORMATTING] --> 
    </div>
    <!-- end #header -->
    <div id="menu">
            <ul>
            <li><a href="Hpage.php">Home</a></li>
            <li><a href="Register.php">Register</a></li>
        </ul>
    </div>
    <!-- end #menu -->
    <div id="page">
    <div id="page-bgtop">
    <div id="page-bgbtm">
    <div id="content">
            <div class="post">
            <div class="post-bgtop">
            <div class="post-bgbtm">
<h1 class="title">PUT HEADING HERE!</h1>
                <div class="entry">
                    <p class="Body">
<?php
$dbname = 'snysbarchive';
$conn= mysql_connect('localhost', 'root', 'usbw');
if (!$conn) {
    echo 'Could not connect to mysql';
    exit;
}

$sql = "SHOW TABLES FROM $dbname";
$result = mysql_query($sql);

if (!$result) {
    echo "DB Error, could not list tables\n";
    echo 'MySQL Error: ' . mysql_error();
    exit;
}
if (mysql_select_db($dbname, $conn))
{
?>
    <form method="post" action="new 2.php">
    <select name="tables">
    <?php
    while ($row = mysql_fetch_row($result)) {
    ?>    
    <?php
        echo '<option value="'.$row[0].'">'.$row[0].'</option>';
    }
    ?>
    </select>
    <input type="submit" value="Show">
</form>
<?php
//mysql_free_result($result);
if (isset($_POST) && isset($_POST['tables']))
{
    $tbl=$_POST['tables'];
    //echo $_POST['tables']."<br />";
    $query="SELECT * from $tbl";
    $res=mysql_query($query);
    echo $query;
    if ($res)
    {
    ?>
    <table border="1">
    <?php
        while ( $row = mysql_fetch_array($res))
        {
            echo "<tr>";
            echo "<td>".$row[0]."</td>";
            echo "<td>".$row[1]."</td>";
            echo "<td>".$row[2]."</td>";
            echo "<td>".$row[3]."</td>";        
            echo "</tr>";
        } ?>
    </table>
    <?php
    }
}
?>
</div>
</div>
            </div>
            </div>

        <div style="clear: both;">&nbsp;</div>
        </div>
        <!-- end #content -->
        <div id="sidebar">
            <ul>
                <li>
                    <h2>Welcome!</h2>
                    <p>Welcome to SNYSBs archive!
                       </p>
                </li>
                <li>
                    <h2>SNYSB</h2>
                    <p>
            <a href="Contact.php">Contact Us!</a>
                    </p>
                </li>
            </ul>
        </div>
        <!-- end #sidebar -->
        <div style="clear: both;">&nbsp;</div>
    </div>
    </div>
    </div>
    <!-- end #page -->
    <div id="footer">
        <p>Copyright (c) 2008 Sitename.com. All rights reserved. Design by <a href="http://www.freecsstemplates.org/">Free CSS Templates</a>.</p>
    </div>
    <!-- end #footer -->
</div>
</body>
</html>

It keeps saying unexpected end but I am not sure how to fix it?

Error Message:Parse error: syntax error, unexpected $end in file on line 128

Thanks

解决方案

You have not selected your database with correct braces around the function.

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