For 循环导致 Task.Run 或 Task.Start 溢出 [英] For Loop result in Overflow with Task.Run or Task.Start
问题描述
有问题,希望有人能帮我.
got a Problem, hope someone can help me out.
我尝试在一个循环中启动 4 个任务,但我收到一个 ArgumentOutOfRangeException:
i try to start 4 Task in an Loop but im getting an ArgumentOutOfRangeException:
for (int i = 0; i < 4; i++)
{
//start task with current connection
tasks[i] = Task<byte[]>.Run(() => GetData(i, plcPool[i]));
}
循环会溢出,因为 i = 4
The Loop gets an Overflow because i = 4
如果我在没有循环的情况下启动任务,它们将毫无问题地运行:
if i start the Tasks without a Loop, they run without any Problems:
tasks[0] = Task<byte[]>.Run(() => GetData(0, plcPool[0]));
tasks[1] = Task<byte[]>.Run(() => GetData(1, plcPool[1]));
tasks[2] = Task<byte[]>.Run(() => GetData(2, plcPool[2]));
tasks[3] = Task<byte[]>.Run(() => GetData(3, plcPool[3]));
不知道为什么?通过套接字连接从西门子 PLC 获取任务数据.PLC 最多支持 32 个连接.我每个连接收到 200 字节.
dont know why? The Tasks GetData from a Siemens PLC via Socket Connection. The PLC Supports up to 32 Connections. I receive 200 Bytes per Connection.
private byte[] GetData(int id, PLC plc)
{
switch (id)
{
case 0:
return plc.ReadBytes(DataType.DataBlock, 50, 0, 200);
case 1:
return plc.ReadBytes(DataType.DataBlock, 50, 200, 200);
case 2:
return plc.ReadBytes(DataType.DataBlock, 50, 500, 200);
case 3:
return plc.ReadBytes(DataType.DataBlock, 50, 700, 200);
case 4:
return plc.ReadBytes(DataType.DataBlock, 50, 900, 117);
default:
return null;
}
}
有什么想法吗?
问候山姆
推荐答案
这可能是由 闭包问题.
试试这个:
for (int i = 0; i < 4; i++)
{
//start task with current connection
int index = i;
tasks[index] = Task<byte[]>.Run(() => GetData(index, plcPool[index]));
}
可能发生的情况是,当最后一个线程开始运行时,循环已经将 i
增加到 4,这就是传递给 GetData()
的值.将 i
的值捕获到一个单独的变量 index
中并使用它应该可以解决这个问题.
What is probably happening is that when the last thread starts running, the loop has already incremented i
to 4, and that's the value that gets passed to GetData()
. Capturing the value of i
into a separate variable index
and using that instead should solve that issue.
举个例子,如果你试试这个代码:
As an example, if you try this code:
public static void Main()
{
Console.WriteLine("Starting.");
for (int i = 0; i < 4; ++i)
Task.Run(() => Console.WriteLine(i));
Console.WriteLine("Finished. Press <ENTER> to exit.");
Console.ReadLine();
}
它通常会给你这样的输出:
it will often give you this kind of output:
Starting.
Finished. Press <ENTER> to exit.
4
4
4
4
将该代码更改为:
public static void Main()
{
Console.WriteLine("Starting.");
for (int i = 0; i < 4; ++i)
{
int j = i;
Task.Run(() => Console.WriteLine(j));
}
Console.WriteLine("Finished. Press <ENTER> to exit.");
Console.ReadLine();
}
你会得到类似的东西
Starting.
Finished. Press <ENTER> to exit.
0
1
3
2
请注意它仍然不是必需的!您将看到打印出的所有正确值,但顺序不确定.多线程很棘手!
Note how it is STILL NOT NECESSARILY IN ORDER! You will see all the correct values printed out, but in an indeterminate order. Multithreading is tricksy!
这篇关于For 循环导致 Task.Run 或 Task.Start 溢出的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!