如何用索引替换张量中的值? [英] How to replace a value within a tensor by indices?

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问题描述

以下代码通过索引向张量内的特定位置添加内容(感谢@mrry 的回答 此处).

The below code add something to a specific location within a tensor by indices (thanks to @mrry's answer here).

indices = [[1, 1]]  # A list of coordinates to update.
values = [1.0]  # A list of values corresponding to the respective
            # coordinate in indices.
shape = [3, 3]  # The shape of the corresponding dense tensor, same as `c`.
delta = tf.SparseTensor(indices, values, shape)

例如,给定这个 -

c = tf.constant([[0.0, 0.0, 0.0],
             [0.0, 0.0, 0.0],
             [0.0, 0.0, 0.0]])

它会在 [1, 1] 处加 1,结果是

It'll add 1 at [1, 1], resulting in

[[0.0, 0.0, 0.0],
[0.0, 1.0, 0.0],
[0.0, 0.0, 0.0]])

问题 - 是否可以替换特定位置的值而不是在该位置添加值?如果在 tensorflow 中不可能,那么在任何其他类似的库中是否可能?

Question - Is it possible to replace the value at a specific location instead of adding at that location? If it's not possible in tensorflow, is it possible in any other similar libraries?

例如

鉴于此 -

[[4.0, 43.1.0, 45.0],
[2.0, 22.0, 6664.0],
[-4543.0, 0.0, 43.0]])

有没有办法将 [1, 1] 处的 22 替换为(比如说)45,从而得到以下结果?

Is there a way to replace the 22 at [1, 1] with (say) 45, resulting in the below?

[[4.0, 43.1.0, 45.0],
[2.0, 45.0, 6664.0],
[-4543.0, 0.0, 43.0]])

推荐答案

这很笨拙,但它确实替换了张量中的值.它基于您提到的这个答案.

This is clunky, but it does replace values in a tensor. It's based on this answer that you mentioned.

# inputs
inputs = tf.placeholder(shape = [None, None], dtype = tf.float32)  # tensor with values to replace
indices = tf.placeholder(shape = [None, 2], dtype = tf.int64)  # coordinates to be updated
values = tf.placeholder(shape = [None], dtype = tf.float32)  # values corresponding to respective coordinates in "indices"

# set elements in "indices" to 0's
maskValues = tf.tile([0.0], [tf.shape(indices)[0]])  # one 0 for each element in "indices"
mask = tf.SparseTensor(indices, maskValues, tf.shape(inputs, out_type = tf.int64))
maskedInput = tf.multiply(inputs, tf.sparse_tensor_to_dense(mask, default_value = 1.0))  # set values in coordinates in "indices" to 0's, leave everything else intact

# replace elements in "indices" with "values"
delta = tf.SparseTensor(indices, values, tf.shape(inputs, out_type = tf.int64))
outputs = tf.add(maskedInput, tf.sparse_tensor_to_dense(delta))  # add "values" to elements in "indices" (which are 0's so far)

它的作用:

  1. 在需要替换为 0 的位置设置输入元素.
  2. 向这些 0 添加所需的值(直接来自此处).

运行检查:

with tf.Session() as sess:
    sess.run(tf.global_variables_initializer())
    ins = np.array([[4.0, 43.0, 45.0], [2.0, 22.0, 6664.0], [-4543.0, 0.0, 43.0]])
    ind = [[1, 1]]
    vals = [45]
    outs = sess.run(outputs, feed_dict = { inputs: ins, indices: ind, values: vals })
    print(outs)

输出:

[[ 4.000e+00  4.300e+01  4.500e+01]
 [ 2.000e+00  4.500e+01  6.664e+03]
 [-4.543e+03  0.000e+00  4.300e+01]]

不像许多否则 很棒 答案 就在那里,这个超出了 tf.Variable()s.

Unlike many otherwise great answers out there, this one works beyond tf.Variable()s.

这篇关于如何用索引替换张量中的值?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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