如何在 ANSI 终端中获取光标的位置? [英] How can I get the cursor's position in an ANSI terminal?

问题描述

我想在终端窗口中获​​取光标的位置.我知道我可以像 这个答案，但我如何在 Python 中做到这一点?

我试过这样这个上下文管理器:

 以 Capturing() 作为输出:sys.stdout.write("\e[6n")打印(输出)

但它只捕获我写的 \e[6n ('\x1b[6n') 转义序列，而不是 ^[[x;yR1 我需要的序列.

我也试过生成一个 subprocess 并获取它的输出，但同样，只有我写的转义序列被捕获:

output = subprocess.check_output(["echo", "\033[6n"], shell=False)打印(输出)

shell=True 使输出为空字符串列表.

避免curses(因为这应该是一个简单，可怜人的光标pos getter)，我怎样才能通过打印\获取返回的转义序列e[6n?

解决方案

我们开始吧 - 您可以自己阅读 sys.stdout 以获取值.我在一个和你一样的问题中找到了答案，但对于一个试图从 C 程序中做到这一点的人:

http://www.linuxquestions.org/questions/programming-9/get-cursor-position-in-c-947833/

所以，当我从 Python 交互式终端尝试一些东西时:

<预><代码>>>>导入系统>>>sys.stdout.write("\x1b[6n");a=sys.stdin.read(10)]^[[46;1R>>>>>>一种'\x1b[46;1R'>>>sys.stdin.isatty()真的

您将不得不使用其他 ANSI 技巧/位置/重印来避免实际显示在终端上的输出，并防止在标准输入读取时发生阻塞 - 但我认为可以通过一些反复试验来完成.

I want to get the cursor's position in a terminal window. I know I can echo -e "\033[6n" and read the output -s silently as in this answer, but how can I do this in Python?

I've tried this contextmanager like this:

with Capturing() as output:
    sys.stdout.write("\e[6n")
print(output)

but it only captures the \e[6n ('\x1b[6n') escape sequence I write, not the ^[[x;yR1 sequence I need.

I've also tried spawning a subprocess and getting its output, but again, only the escape sequence I write is captured:

output = subprocess.check_output(["echo", "\033[6n"], shell=False)
print(output)

shell=True makes the output be a list of empty strings.

Avoiding curses (because this is supposed to be a simple, poor man's cursor pos getter), how can I get the escape sequence returned by printing \e[6n?

解决方案

Here we go -you can simply read sys.stdout yourself to get the value. I found the answer in a question just like yours, but for one trying to do that from a C program:

http://www.linuxquestions.org/questions/programming-9/get-cursor-position-in-c-947833/

So, when I tried something along that from the Python interactive terminal:

>>> import sys
>>> sys.stdout.write("\x1b[6n");a=sys.stdin.read(10)
]^[[46;1R
>>>
>>> a
'\x1b[46;1R'
>>> sys.stdin.isatty()
True   

You will have to use other ANSI tricks/position/reprint to avoid the output actually showing up on the terminal, and prevent blocking on stdin read - but I think it can be done with some trial and error.

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