嵌套列表中的 Terraform 嵌套循环 [英] Terraform nested loop in nested list

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本文介绍了嵌套列表中的 Terraform 嵌套循环的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试创建一种动态方法,以在将由最终用户配置的多个环境中创建虚拟机.尝试使用嵌套循环进行循环.扁平化函数、计数等,但还没有找到达到我目标的方法.我有以下结构的 terrafrom.tfvars:

I'm trying to create a dynamic method to create vms in multiple environments that will be configured by the end user. Tried for loops with nested loops. flatten function, count, etc but haven't found a way to reach my goal. I have terrafrom.tfvars with the follwing structure:

Bigip_devices = {
    main_hub = {
      region             = "eastus"
      azs                = ["1"]            #Azure availabilty zones
      vnet_name               = "vnet-main"   # Vnet name to deploy to
      bigip_instance_count = 2            # Number of instnaces to delpoy
      cluster             = "yes"         # Deploy as a cluster or stand alone device
      version             = ""            # Leave blank for default value
      sku                 = ""            # Leave blank for default value - f5-bigip-virtual-edition-25m-best-hourly
      offer               = ""            # Leave blank for default value - f5-big-ip-best
      instance_type       = ""            # Leave blank for default value - Standard_DS3_v2
      disable_password_authentication = ""     #Leave blank for default value
      tags                = ""
    }
    spoke = {
      region             = "eastus"
      azs                = ["1","2"]            #Azure availabilty zones
      vnet_name               = "vnet-spoke"   # Vnet name to deploy to
      bigip_instance_count = 4            # Number of instnaces to delpoy
      cluster             = "yes"         # Deploy as a cluster or stand alone device
      version             = ""            # Leave blank for default value
      sku                 = ""            # Leave blank for default value - f5-bigip-virtual-edition-25m-best-hourly
      offer               = ""            # Leave blank for default value - f5-big-ip-best
      instance_type       = ""            # Leave blank for default value - Standard_DS3_v2
      disable_password_authentication = ""     #Leave blank for default value
      tags                = ""
    }
  }

迭代列表中的每个键(在示例中是 2 个键 - 主集线器和辐条)并创建与 bigip_instance_count 设置相对应的虚拟机数量的正确方法是什么.在上面的例子中,我想创建 2 个环境,一个有 2 个设备,第二个有 4 个设备.有没有办法实现它?

What is the correct method to iterate each key in the list( in the example the are 2 keys - main hub and spoke) and to create the amount of virtual machines corresponding to the bigip_instance_count setting. In the above example, I want to create 2 environments, one with 2 devices and the second with 4 devices. Is there a way to achieve it?

推荐答案

如果您将上述复杂的 JSON 转换为一个集合,其中每个要创建的资源都有一个元素,那将会非常方便.为此,您可以使用 flatten 函数.

It would be really convenient if you transform the above complex JSON into a collection that has one element per resource you want to create. To achieve this, you could use the flatten function.

locals {
  # A list of objects with one object per instance.
  flattened_values = flatten([
    for ip_key, ip in var.Bigip_devices : [
      for index in range(ip.bigip_instance_count) : {
        region  = ip.region
        azs            = ip.azs
        ip_index      = index
        ip_key        = ip_key
        cluster         = ip.cluster
        version        = ip.version
        sku   = ip.sku
        offer = ip.offer
        instance_type = ip.instance_type
        disable_password_authentication = ip.disable_password_authentication
        tags = ip.tags
      }
    ]
  ])
}

通过上面的flattened函数,你会得到下面你想要创建的资源集合列表.

With the above flattened function, you get below list of collection of resources, you would like to create.

flattened_value_output = [
  {
    "azs" = [
      "1",
    ]
    "cluster" = "yes"
    "disable_password_authentication" = ""
    "instance_type" = ""
    "ip_index" = 0
    "ip_key" = "main_hub"
    "offer" = ""
    "region" = "eastus"
    "sku" = ""
    "tags" = ""
    "version" = ""
  },
  {
    "azs" = [
      "1",
    ]
    "cluster" = "yes"
    "disable_password_authentication" = ""
    "instance_type" = ""
    "ip_index" = 1
    "ip_key" = "main_hub"
    "offer" = ""
    "region" = "eastus"
    "sku" = ""
    "tags" = ""
    "version" = ""
  },
  {
    "azs" = [
      "1",
      "2",
    ]
    "cluster" = "yes"
    "disable_password_authentication" = ""
    "instance_type" = ""
    "ip_index" = 0
    "ip_key" = "spoke"
    "offer" = ""
    "region" = "eastus"
    "sku" = ""
    "tags" = ""
    "version" = ""
  },
  {
    "azs" = [
      "1",
      "2",
    ]
    "cluster" = "yes"
    "disable_password_authentication" = ""
    "instance_type" = ""
    "ip_index" = 1
    "ip_key" = "spoke"
    "offer" = ""
    "region" = "eastus"
    "sku" = ""
    "tags" = ""
    "version" = ""
  },
  {
    "azs" = [
      "1",
      "2",
    ]
    "cluster" = "yes"
    "disable_password_authentication" = ""
    "instance_type" = ""
    "ip_index" = 2
    "ip_key" = "spoke"
    "offer" = ""
    "region" = "eastus"
    "sku" = ""
    "tags" = ""
    "version" = ""
  },
  {
    "azs" = [
      "1",
      "2",
    ]
    "cluster" = "yes"
    "disable_password_authentication" = ""
    "instance_type" = ""
    "ip_index" = 3
    "ip_key" = "spoke"
    "offer" = ""
    "region" = "eastus"
    "sku" = ""
    "tags" = ""
    "version" = ""
  },
]

从上面的集合中,你可以迭代 &使用如下唯一键创建资源::

From the above collection, you could iterate & create resources with unique keys like below::

resource "some_resource" "example" {
  for_each = {
    # Generate a unique string identifier for each instance
    for ip in local.flattened_value_output : format("%s-%02d", ip.ip_key, ip.ip_index + 1) => ip
  }
}

这样可以保证资源的创建或更新,因为每个资源都使用唯一的密钥.

This way, the creation or updating of resources is guaranteed as each resource uses a unique key.

更多详情请参考这个讨论 我与 Hashicorp 人员进行了讨论.

For more details, refer this discussion I had with Hashicorp personnel.

这篇关于嵌套列表中的 Terraform 嵌套循环的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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