我可以在不阻塞主执行线程的情况下以编程方式启动 WSGI 应用程序服务器吗? [英] Can i programmatically start a WSGI application server without blocking the main thread of execution?

问题描述

我正在用 python 编写一个 Web 应用程序，并使用 lettucesplinter 为其编写验收测试.

I'm writing a web application in python, and using lettuce with splinter to write acceptance tests for it.

为了做到这一点，我需要一个 wsgi 服务器在后台启动我的应用程序，以便应用程序可用于我的测试套件.为此，我一直在另一个线程中启动一个女服务员服务器实例，以便浏览器连接到:

In order to do this, I need to get a wsgi server to start my application in the background, so that the application is available for my test suite. To do this, I've been spinning up a waitress server instance in another thread, for the browser being driven to connect to:

def setUp():
    base = os.path.dirname(__file__) + "/../../.."
    world.app = loadapp('config:test.ini', relative_to=base)
    world.server_thread = thread.start_new_thread(serve_app,  (world.app,))

def serve_app(app):
    serve(app, host='0.0.0.0', port=7654)

这非常有效 - 正在运行的应用程序实例可用于我的测试套件以设置装置/模拟等，并且服务器可用于我的测试连接.但是，当测试完成时，我无法向服务器发送信号以彻底关闭自身.因此，无论如何我可以以某种方式将 KeyboardInterrupt 发送到我生成的服务器线程(它将被女服务员捕获并提示它干净地关闭)，或者失败了，是否存在现有的wsgi 服务器实现，它公开了非阻塞的 start() 和 stop() 方法，我可以使用它们代替女服务员?

This works quite nicely - The running application instance is available to my test suite in order to set up fixtures / mocks etc, and the server is available for my tests to connect to. However, when the tests finish, I've no way of sending a signal to the server to shut itself down cleanly. Therefore, is there anyway I can somehow either send a KeyboardInterrupt to the server thread I spawn (which will be caught by waitress and will prompt it to shut down cleanly), or failing that, is there an existing wsgi server implementation which exposes non-blocking start() and stop() methods that I could employ instead of waitress?

推荐答案

将运行 WSGI 服务器的线程标记为守护线程.这样，当您退出主线程时，它不会等待服务器正在运行的线程完成，而只会退出应用程序.

Mark the thread you run the WSGI server in as a daemon thread. That way when you exit the main thread it will not wait for the thread the server is running in to complete and will just exit the application.

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