在java中的特定位置拆分字符串 [英] Splitting a string at a particular position in java

问题描述

假设您有一个 "word1 word2 word3 word4" 形式的字符串.拆分它的最简单方法是什么，split[0] = "word1 word2" 和 split[1] = "word3 word4"?

Assume you have a string of the form "word1 word2 word3 word4". What is the simplest way to split it such that split[0] = "word1 word2" and split[1] = "word3 word4"?

澄清

我想拆分，而不是 split[0] = "word1"，我有前 2 个词(我同意它不清楚)和 split[1] 中的所有其他词，即在第二个空格

I want to split such that instead of having split[0] = "word1", I have the first 2 words (I agree it was not clear) and all the other words in split[1], ie on the second space

推荐答案

我会使用 String.substring(beginIndex, endIndex);和 String.substring(beginIndex);

I would use the String.substring(beginIndex, endIndex); and String.substring(beginIndex);

String a = "word1 word2 word3 word4";
int first = a.indexOf(" ");
int second = a.indexOf(" ", first + 1);
String b = a.substring(0,second);
String c = b.subString(second); // Only startindex, cuts at the end of the string

这将导致 a = "word1 word2" 和 b = "word3 word4"

This would result in a = "word1 word2" and b = "word3 word4"

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