将数字值与文本值分开 [英] Separating Numeric values from Text Values

问题描述

我正在从 REST API 检索信息并显示:

I am retrieving information from a REST API and it displays:

"Per 78g - Calories: 221kcal | Fat: 12.65g | Carbs: 16.20g | Protein: 10.88g"

我已将这些项目导入到 ListView 中，当用户单击一个项目时，我想将每个数值单独串起来，如下所示，没有它们的文本.基于上面的例子:

I have imported the items into a ListView and when a user clicks an item I would like to string each numeric value individually like below without their text. Based on the example above:

String calories = 221;
String fat = 12.65;
String carbs = 16.20;
String protein = 10.88;

我摆脱了每 78 克":

I got rid of the "Per 78g" with:

String sd = food.getString("food_description");
String[] row = sd.split("-");
tems.add(new Item(food.getString("food_name"), row[1]));

在每个列表项中显示以下内容.

Which displays the following in each list item.

"Calories: 221kcal | Fat: 12.65g | Carbs: 16.20g | Protein: 10.88g"

当用户单击列表项时:我如何正确地将其分开并同时消除文本?一旦我单独获得数值，我会没事的.

When the User clicks on a list Item: How do I separate this properly and eliminate the text as well? Once I get the numeric values individually I would be fine.

@Override
public void onItemClick(AdapterView<?> arg0, View arg1, int arg2, long arg3) {
    // TODO Auto-generated method stub

    String calories = adapter.getItem(arg2).getDescription();

    String[] calRow = calories.split("?|?");

    Toast.makeText(getActivity(), "" + calRow[1], Toast.LENGTH_LONG).show();

    mCallback.onFoodSelected(adapter.getItem(arg2).getTitle(), calRow[1]);
}

API 文档非常糟糕且过时.我正在使用它，因为它有很好的信息.对于认为这是不好的做法的每个人，这是返回 JSON 的示例:

The API documentation is really bad and outdated. I am using it because it has great information. For everyone that believes this is bad practice this is the example return JSON:

{  
   "foods":{  
      "food":{  
         "food_description":"Per 342g - Calories: 835kcal | Fat: 32.28g | Carbs: 105.43g | Protein: 29.41g",
         "food_id":"4384",
         "food_name":"Plain French Toast",
         "food_type":"Generic",
         "food_url":"http:\/\/www.fatsecret.com\/calories-nutrition\/generic\/french-toast-plain"
      },
      "max_results":"20",
      "page_number":"0",
      "total_results":"228"
   }
}

推荐答案

按如下方式更改您的 JSON，将使您的工作更轻松:

Changing your JSON as follows, will make your job more easier:

{  
   "foods":{  
      "food":{  
         "food_description":{
            "Per" : "342g",
            "Calories": "835kcal",
            " Fat": "32.28g",
            "Carbs":" 105.43g",
            " Protein": "29.41g"
            },
         "food_id":"4384",
         "food_name":"Plain French Toast",
         "food_type":"Generic",
         "food_url":"http:\/\/www.fatsecret.com\/calories-nutrition\/generic\/french-toast-plain"
      },
      "max_results":"20",
      "page_number":"0",
      "total_results":"228"
   }
}

我假设你知道如何解析它.
如果您无法更改 json，请尝试使用 StringTokenizer 或使用 String.split().

I am assuming you know how to parse it.
And in case you are not able to change your json, try to use StringTokenizer or use String.split().

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