编辑大文本文件中的单行 [英] Editing a single line in a large text file

问题描述

所以我需要记录一组 4 个整数，它们的值在一天中的每一秒都不同.即:

So I need to record a set of 4 integers whose values are different for every second of the day. i.e.:

#Here the values are initialized to the same value, however they will change as samples are taken
data = [[.25 for numData in range(4)] for numSecs in range(86400)]

显然，第一个索引长度为 86400 的二维数组(gah it python, LIST)是非常不切实际的.相反，我想创建一个 86400 行的文本文件，格式如下:

Now obviously a two dimensional array(gah its python, LIST) whose first index length is 86400 is quite impractical. Instead I want to create a text file with 86400 lines formatted as such:

numSec data0 data1 data2 data3

0 .25 .25 .25 .25
1 .25 .25 .25 .25
2 .25 .25 .25 .25
...

并且在采集样本时，我希望能够编辑此文件，不，我希望能够编辑 numSec = 采集样本的第二行的文件行.例如，在 numSec = 2(午夜后 2 秒)处采集的样本将导致我的程序编辑文件，以便:

And as samples are taken, I want to be able to edit this file, nay, I want to be able to edit the line of the file whose numSec = the second the sample was taken. For example, a sample taken at numSec = 2 (2 seconds after midnight) would cause my program to edit the file so that:

0 .25 .25 .25 .25
1 .25 .25 .25 .25
2 .70 .10 .10 .10
...

似乎很容易，我什至阅读了一堆帖子，这些帖子演示了如何在文本文件中重写单个文件.问题是，它们都要求您阅读整个文件.我不希望我的程序每秒读取 86,400 行.

Seems easy enough, I have even read a bunch of posts which demonstrated how to rewrite a single in a text file. The problem is, they all require that you read in the whole file. I don't want my program to be reading 86,400 lines every second.

因此我们得出了我的问题:我可以读取文本文件中的一行，对其进行编辑，然后将其写回文件，而无需每次需要进行更改时都读取整个文件吗?

Thus we arrive at my question: Can I read a single line in a text file, edit it, and write it back to the file, without reading the entire file every single time a change needs to be made?

附言我应该注意我正在运行 Ubuntu 12.04(精确)，这是用于 ROS 节点

P.S. I should note I am running Ubuntu 12.04 (Precise) and this is for use in a ROS node

P.P.S 该程序将运行任意天数，因此可以多次读取和重写每一秒"数据.我想使用文件的另一个原因是，如果系统需要关闭，我想在下次运行时保存发行版.

P.P.S This program will be running for an arbitrary amount of days so each "second" of data could be read and rewritten many times. Also another reason I would like to use a file is if the system needs to be shut off, I would like to save the distributions for the next time it is run.

推荐答案

您可能需要稍微修改一下，它假定所有行的长度相同.为此，我必须将第一列填充到固定宽度.但是，如果您不想填充，您应该能够计算特定行之前的 1、2、3、4、.. 位数.

You may need to modify this a bit and it assume that all lines are of the same length. For this, I had to pad the first column to a fixed width. But if you don't want padding you should be able to calculate the number of 1,2,3,4,.. digit numbers before a particular row.

data = [[.25 for numData in range(4)] for numSecs in range(86400)]
length_line=0

def write_line(f, sec, data):
    line="{:6d}".format(sec) + " " +" ".join(
            ["{:.2f}".format(dd) for dd in data])+"\n"
    f.write(line)
    return len(line)

with open('output', 'w') as of:
    for i,d in enumerate(data):
        length_line=write_line(of, i, d)

with open('output', 'rb+') as of:
    # modify the 2nd line:
    n = 2
    of.seek(n*length_line)
    write_line(of, n, [0.10,0.10,0.10,0.10])
    # modify the 10th line:
    n = 10
    of.seek(n*length_line)
    write_line(of, n, [0.10,0.10,0.10,0.10])

这篇关于编辑大文本文件中的单行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！