“蚕食"最有效的方式文本文档中的第一行文本,然后将其重新保存在 python 中 [英] Most efficient way to "nibble" the first line of text from a text document then resave it in python
问题描述
我有一个文本文档,我想每隔 30 秒左右重复删除第一行文本.
I have a text document that I would like to repeatedly remove the first line of text from every 30 seconds or so.
我已经编写(或更准确地说是复制了)python 可重置计时器对象的代码,该对象允许在不要求重置或取消的情况下以非阻塞方式每 30 秒调用一次函数.
I have already written (or more accurately copied) the code for the python resettable timer object that allows a function to be called every 30 seconds in a non blocking way if not asked to reset or cancel.
(如果有人可以检查我实现重复的方式,那没关系,因为我的 python 在运行时有时会崩溃,将不胜感激:))
(If someone could check the way I implemented the repeat in that is ok, because my python sometimes crashes while running that, would be appreciated :))
我现在想编写我的函数来加载一个文本文件,并可能复制除第一行之外的所有内容,然后将其重写为同一个文本文件.我可以这样做,我认为这样...但它是最有效的吗?
I now want to write my function to load a text file and perhaps copy all but the first line and then rewrite it to the same text file. I can do this, this way I think... but is it the most efficient ?
def removeLine():
with open(path, 'rU') as file:
lines = deque(file)
try:
print lines.popleft()
except IndexError:
print "Nothing to pop?"
with open(path, 'w') as file:
file.writelines(lines)
这行得通,但这是最好的方法吗?
This works, but is it the best way to do it ?
推荐答案
我会使用 fileinput
模块 with inplace=True
:
import fileinput
def removeLine():
inputfile = fileinput.input(path, inplace=True, mode='rU')
next(inputfile, None) # skip a line *if present*
for line in inputfile:
print line, # write out again, but without an extra newline
inputfile.close()
inplace=True
导致 sys.stdout
被重定向到打开的文件,所以我们可以简单地打印"这些行.
inplace=True
causes sys.stdout
to be redirected to the open file, so we can simply 'print' the lines.
next()
调用用于跳过第一行;给它一个默认的 None
会抑制一个空文件的 StopIteration
异常.
The next()
call is used to skip the first line; giving it a default None
suppresses the StopIteration
exception for an empty file.
这使得重写大文件更加高效,因为您只需要将fileinput
readlines 缓冲区保留在内存中.
This makes rewriting a large file more efficient as you only need to keep the fileinput
readlines buffer in memory.
我认为根本不需要 deque
,即使对于您的解决方案;只需在那里使用 next()
,然后使用 list()
来捕获剩余的行:
I don't think a deque
is needed at all, even for your solution; just use next()
there too, then use list()
to catch the remaining lines:
def removeLine():
with open(path, 'rU') as file:
next(file, None) # skip a line *if present*
lines = list(file)
with open(path, 'w') as file:
file.writelines(lines)
但这需要你读取内存中的所有文件;不要对大文件这样做.
but this requires you to read all of the file in memory; don't do that with large files.
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