值既不是一个数组，也不是一个指针 [英] value is neither an array nor a pointer

问题描述

我有这样的code：

int ID [STUDENTS];
int Scores [STUDENTS][GRADES];
int Hi [GRADES];
int Lo [GRADES];
double Avg [GRADES];
int numStudents;

/*getData function called*/
int getData(ID, Scores,  numStudents)
{
  int student_count;
  int quiz_count;

  FILE* spIn;


  spIn = fopen("myfile.dat", "r");
  student_count=0;
  while (fscanf (spIn, "%d", ID[student_count]) != EOF)
  {
     for (quiz_count = 0; quiz_count < GRADES; quiz_count++)
     {
        fscanf (spIn, "%d", Scores[student_count][quiz_count]);
     }
  }
}

我不断收到错误标题行：而（！的fscanf（SPIN，％D，ID [STUDENT_COUNT）= EOF）和的fscanf（SPIN，％D，成绩[STUDENT_COUNT] [quiz_count]）;

请帮我不知道该怎么办！

Please help I don't know what to do!

推荐答案

问题是与变量的作用域 ID 和分数。两个变量都在两个地方定义 -

The problem is with the scope of variables ID and Scores. Both variables are defined in two places -

• 正如在文件的顶端一个全局变量，和


• 作为命名的参数给你的函数。

命名参数是在范围接近使用的地方，因此，它赢得

The named parameter is closer in scope to the place of use, hence it wins.

它看起来像在第二位的使用（即作为函数参数）不是故意的，因为缺乏声明的类型 ^* 。删除它们会使你的code编译。

It looks like the use in the second place (i.e. as function parameter) is not intentional, because the declarations lack types^*. Removing them will make your code compile.

^* 在这种情况下，C中视为它们 INT s和问题，这应该解释了错误给你一个警告：因为编译器认为该内部范围的 ID 和分数是 INT 取值，你不能使用索引操作符 [] 他们。

^* in which case C considers them ints, and issues a warning which should have explained the error to you: since the compiler thinks that the inner-scope ID and Score are ints, you cannot use index operator [] with them.

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