怎么找到的话，它基于一个列表之后取消（删除）字符？ [英] How find words and abolish (delete) characters after it based in a list?

问题描述

如果我想查PHP字符串中的存在，并且删除之后我可以使用的话：

If I want to check 'php' exist in a string and delete the words after it I could just use:

$string = 'hello world php is a bla bla..';
$string = explode(' php ', $string);
echo $string[0];

但是，如果我有多个字，而不是仅仅PHP？例如以下几首歌的名字有功勋，壮举，金融时报，英尺..这是他们四个人。

But what if I have multiple words instead of just 'php'? For example few song name below has 'feats','feat','ft','ft.'.. that's four of them.

我要让像新航 - 弹性壮举brunos火星变成只是SIA - 弹性。

I want to make like 'sia - elastic feat brunos mars' become just 'sia - elastic'.

推荐答案

这是你所需要的code：

This is the code that you need:

<?php

$string = 'sia - elastic feat brunos mars';

$array = array('feats', 'feat', 'ft', 'ft.');

for($i = 0; $i < count($array); $i++) {
  $out = explode(' ' . $array[$i] . ' ', $string);
  if (count($out) > 1) {
       break;
  }   
}

echo $out[0];

?>

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