迅速字典人口问题：类型AnyObject“不符合协议”NSCopying“ [英] swift dictionary population issue: type 'AnyObject' does not conform to protocol 'NSCopying'

问题描述

我试图从迁移Objetive-C斯威夫特下一个code：

I am trying to migrate the next code from Objetive-C to Swift:

   NSArray *voices = [AVSpeechSynthesisVoice speechVoices];
    NSArray *languages = [voices valueForKey:@"language"];

    NSLocale *currentLocale = [NSLocale autoupdatingCurrentLocale];
    NSMutableDictionary *dictionary = [NSMutableDictionary dictionary];
    for (NSString *code in languages)
    {
        dictionary[code] = [currentLocale displayNameForKey:NSLocaleIdentifier value:code];
    }

和我做了以下内容：

var voices:NSArray = AVSpeechSynthesisVoice.speechVoices()
var languages:NSArray=voices.valueForKey("language") as NSArray

var currentLocale:NSLocale=NSLocale.autoupdatingCurrentLocale()
var dictionary:NSMutableDictionary=NSMutableDictionary()

for code in languages {
   var name=currentLocale.displayNameForKey(NSLocaleIdentifier, value: code)
   dictionary[code]=name
}

和我收到以下错误：

错误：类型AnyObject不符合协议NSCopying
    字典[code =名称

我不知道如何申报字典对象，做与国家codeS字符串作为键和一个小的描述数组一样简单。
像

I don’t know how to declare the dictionary object, to do something as simple as an array with country codes strings as key and a small description. like

词典[ES-ES] = [西班牙]
   词典[EN-US] = [美国英语]

dictionary["es-ES"]=["Spanish"] dictionary["en-US"]=["American English"]

推荐答案

的NSDictionary 键需要符合 NSCopying ，但 AnyObject 不一定。 （的NSArray 收益 AnyObject S IN斯威夫特）使用为<！/ code>在 code 变量运营商，以确保它是：

NSDictionary keys need to conform to NSCopying, but AnyObject doesn't necessarily. (NSArray returns AnyObjects in Swift.) Use the as! operator on your code variable to be sure that it is:

dictionary[code as! NSCopying] = name

您也可以向下转换的语言阵列 [字符串] ，并避免在分配$ C $投C。

You can also downcast the language array to [String] and avoid the cast in the assignment code.

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