如何将自纪元以来的 Unix 时间/时间转换为标准日期和时间? [英] How to convert Unix time / time since the epoch to standard date and time?

问题描述

我正在使用chrono crate；经过一番挖掘，我发现 DateTime 类型有一个函数 timestamp()，它可以生成 i64 类型的纪元时间.但是，我不知道如何将其转换回 DateTime.

I'm using the chrono crate; after some digging I discovered the DateTime type has a function timestamp() which could generate epoch time of type i64. However, I couldn't find out how to convert it back to DateTime.

extern crate chrono;
use chrono::*;

fn main() {
    let date = chrono::UTC.ymd(2020, 1, 1).and_hms(0, 0, 0);
    println!("{}", start_date.timestamp());
    // ...how to convert it back?
}

推荐答案

你首先需要创建一个NaiveDateTime，然后再用它创建一个DateTime:

You first need to create a NaiveDateTime and then use it to create a DateTime again:

extern crate chrono;
use chrono::prelude::*;

fn main() {
    let datetime = Utc.ymd(2020, 1, 1).and_hms(0, 0, 0);
    let timestamp = datetime.timestamp();
    let naive_datetime = NaiveDateTime::from_timestamp(timestamp, 0);
    let datetime_again: DateTime<Utc> = DateTime::from_utc(naive_datetime, Utc);

    println!("{}", datetime_again);
}

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