两次时间差导致错误 [英] Difference between two time resulting an error

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本文介绍了两次时间差导致错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有这种情况,我想计算一个员工的迟到时间并得到迟到,我需要减去时间来得到一个员工迟到的分钟/小时.

I have this situation, i want to calculate the late of an employee and to get the late, i need to Subtract time to get the minute/hour late of an employee.

假设是..我有这个代码:

Suppose to be.. i have this code:

$time = strtotime($time_in);        
$late_time = date("H:i", strtotime('+15 minutes', $time));  

if(date("H:i:s",strtotime($time_duty[0]->time)) > $late_time ) {                
        $time_difference = (date("H:i:s",strtotime($time_duty[0]->time)) - $late_time)/60;
        print_r($time_difference);          
}

然后我遇到了错误

消息:遇到格式不正确的数值

Message: A non well formed numeric value encountered

推荐答案

试试这个:

$time = strtotime($time_in);    
$datetime1 = new DateTime(date("H:i:s",strtotime($time_duty[0]->time)));
$datetime2 = new DateTime(date("H:i:s", strtotime('+15 minutes', $time)));
$interval = $datetime1->diff($datetime2);
echo $interval->format('H:i:s');

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