两次时间差导致错误 [英] Difference between two time resulting an error
本文介绍了两次时间差导致错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有这种情况,我想计算一个员工的迟到时间并得到迟到,我需要减去时间来得到一个员工迟到的分钟/小时.
I have this situation, i want to calculate the late of an employee and to get the late, i need to Subtract time to get the minute/hour late of an employee.
假设是..我有这个代码:
Suppose to be.. i have this code:
$time = strtotime($time_in);
$late_time = date("H:i", strtotime('+15 minutes', $time));
if(date("H:i:s",strtotime($time_duty[0]->time)) > $late_time ) {
$time_difference = (date("H:i:s",strtotime($time_duty[0]->time)) - $late_time)/60;
print_r($time_difference);
}
然后我遇到了错误
消息:遇到格式不正确的数值
Message: A non well formed numeric value encountered
推荐答案
试试这个:
$time = strtotime($time_in);
$datetime1 = new DateTime(date("H:i:s",strtotime($time_duty[0]->time)));
$datetime2 = new DateTime(date("H:i:s", strtotime('+15 minutes', $time)));
$interval = $datetime1->diff($datetime2);
echo $interval->format('H:i:s');
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