python selenium - 当它找不到元素时需要很多时间 [英] python selenium - takes a lot of time when it does not find elements

问题描述

我的代码使用 chromedriver 扫描了很多网页，并使用find_elements_by_xpath"在每个页面中搜索相同的元素

my code scans a lot of internet pages with chromedriver and searches for the same element in each page with "find_elements_by_xpath"

Lines = driver.find_elements_by_xpath(
                    '//*[@id="top"]/div[contains(@style, "display: block;")]/'
                    'div[contains(@style, "display: block;")]//tbody//a[contains(@title, "Line")]')

当它找到一个或多个时，它运行得又快又好.但是，当 XPath 不存在时，它会运行 6-7 秒，然后继续前进.

When it finds, one or multiple, it works fast and good. But, when the XPath doesn't exist it runs for 6-7 seconds and then moves on.

我可以将搜索限制在 1 秒内，如果一秒内没有找到，就继续吗?有没有办法做到这一点?

Can I limit the search for 1 second, And if it doesn't find in a second, just move on? Is there a way to do this?

推荐答案

尝试使用 ExplicitWait 如下:

from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait as wait
from selenium.common.exceptions import TimeoutException

try:
    Lines = wait(driver, 1).until(EC.presence_of_all_elements_located((By.XPATH, '//*[@id="top"]/div[contains(@style, "display: block;")]/'
                'div[contains(@style, "display: block;")]//tbody//a[contains(@title, "Line")]')))
except TimeoutException:
    pass

这应该允许您等待 1 秒钟，直到找到至少一个元素并获取所需的 WebElements 列表，否则什么都不做

This should allow you to wait for 1 second until at least one element found and get the list of required WebElements or do nothing otherwise

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