Java 计时器和动作监听器 [英] Java Timers and actionlisteners

问题描述

Baiscilly，我正在为一个项目制作这个游戏，我无法弄清楚如何让计时器工作，这是我的代码尝试.

Baiscilly, I'm making this game for a project, and I can't fiure out how to get timers to work whatsoever, here is my code attempting.

import java.awt.event.*;
import java.util.Timer;

public class Timers {
    private int timeLeft = 60;
    private void timer() {
        while(timeLeft > 0){
             int delay = 1000;
              ActionListener taskPerformer = new ActionListener() {
                  public void actionPerformed(ActionEvent evt) {
                      timeLeft--;
                  }{
              new Timer(delay, taskPerformer).start();
              };
    };
}
}
}

我不知道自己做错了什么，也不知道接下来要做什么.除此之外，我需要制作一个 Actionlistener 看看用户的答案是否与预设的答案相同.

I don't know what I'm doing wrong or what to do next. As well as this i need to make an Actionlistener see if the users answer is the same as the preset answer.

import javax.swing.*;

import java.awt.event.*;

...

    JTextField Janswer = new JTextField();
    Janswer.setBounds(110, 70, 150, 25);
    newFrame.add(Janswer);
    if Janswer = equations.getanswer(){
        score++;

我想如果我付出这么多，我也可以告诉你从哪里得到答案

And I guess if i'm giving this much I may as well give you where it is getting the answers from

public class Equations {
    private static String equation;
    private int answer;
    Problems problem = new Problems();

    public Equations() {
        equation = problem.getFirstNumber() + " " + problem.getSign() + " " + problem.getSecondNumber();
        String sign = problem.getSign();
        if (sign.equals("+"))
            answer = problem.getFirstNumber() + problem.getSecondNumber();
        else if (sign.equals("-"))
            answer = problem.getFirstNumber() - problem.getSecondNumber();
        else if (sign.equals("*"))
            answer = problem.getFirstNumber() * problem.getSecondNumber();
    }

    public static String getEquations() {
        return equation;
    }
    public int getAnswer() {
        return answer;
    }
}

感谢大家为我提供的任何帮助，如果我需要以任何方式更改帖子，请告诉我，我是新手！

Thank you all for any help you're able to give me, and just let me know if I need to change my post in any way, I'm new to this!

推荐答案

主要问题是你使用了一个 while-loop，它正在创建一堆新的 Timer> s 在每次迭代中都在减少 timeLeft 值.你只需要一个 Timer.

The main problem is you are using a while-loop, which is creating a bunch of new Timers on each iteration, which are all decrementing the timeLeft value. You only need a single Timer.

根据你想要做什么，你可以做类似......

Depending on what you want to do, you could do something like...

ActionListener taskPerformer = new ActionListener() {
    public void actionPerformed(ActionEvent evt) {
        System.out.println("Time's up!");
    }
};
new Timer(60 * 1000, taskPerformer).start();

这将在 1 分钟内建立一个回调，这可以让您定义超时...

This will establish a call back in 1 minutes time, which can allow you to define a timeout...

知道，如果你想要一个倒数计时器，你可以这样做......

Know, if you want a count down timer, you could do something like...

ActionListener taskPerformer = new ActionListener() {
    public void actionPerformed(ActionEvent evt) {
        count++;
        if (count >= 59) {
            ((Timer)evt.getSource()).stop();
            System.out.println("Time's up!");
        }
    }
};
new Timer(1000, taskPerformer).start();

基本上计数到 60(从 0)并且每秒更新一次(您必须使用 60 - count 来获取倒计时值)...

Which basically counts to 60 (from 0) and is updated every second (you'd have to use 60 - count to get the count down value)...

有关详细信息，请参阅如何使用 Swing 计时器

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