使用“xlsx"读取时间戳时出错包裹 [英] Error reading timestamps using "xlsx" package

问题描述

Excel 文件中的数据看起来像

Data in Excel file looks like

TIMESTAMP           TYPE BID BIDSIZ
2015-01-04 09:00:00 BID 365    10
2015-04-01 09:00:05 BID 367.8  55
2015-04-01 09:00:33 BID 365    10
2015-04-01 09:00:36 BID 367.8  55

当我运行以下代码时:

require(xlsx)
f1<-read.xlsx2("Canara_Data.xlsx", sheetName = "BID")
f1$TIMESTAMP<-as.POSIXct(f1$TIMESTAMP, format="%Y-%M-%D %H:%M:S")

查看它会导致 TIMESTAMP 看起来像

viewing it causes TIMESTAMP to look like

View(`f1`)

TIMESTAMP   X.  BID BIDSIZ
42008.375   BID 365 10
42095.37505787037   BID 367.8   55
42095.37538194445   BID 365 10
42095.37541666667   BID 367.8   55

str(f1)
# 'data.frame': 18214 obs. of  4 variables:
#  $ TIMESTAMP: POSIXct, format: NA NA ...
#  $ TYPE   : Factor w/ 1 level "BID": 1 1 1 1 1 1 1 1 1 1 ...
#  $ BID    : Factor w/ 344 levels "365","365.1",..: 1 55 1 55 1 55 1 55 59 1 ...
#  $ BIDSIZ : Factor w/ 1259 levels "1","10","100",..: 2 854 2 854 2 854 2 854 4 2

请帮助将 TIMESTAMP 作为日期读取，格式为%Y-%M-%D %H:%M:S"，以及 BID 和 BIDSIZ 作为字符.

Please help in making TIMESTAMP to be read as date with the format "%Y-%M-%D %H:%M:S", and also BID and BIDSIZ as character.

推荐答案

Use Package readxl

Use Package readxl

excel_sheets("C:\\Users\\Gaurav Kumar\\Documents\\Canara_Data.xlsx")
grv<-read_excel("C:\\Users\\Gaurav Kumar\\Documents\\Canara_Data.xlsx", sheet = 1, col_names = TRUE, col_types = NULL, na = "", skip = 0)

它也会读取时间戳.它在将 excel 转换为 csv 时节省了大量时间，知道 CSV 在保存时间戳方面存在问题.

and it will read the Timestamps too. It saves huge time in converting the excel to csv, knowing CSV has a problem in saving timestamps.

              TIMESTAMP EX  BID BIDSIZ
1   2015-04-01 09:00:00 N   365.00  10
2   2015-04-01 09:00:05 N   367.80  55
3   2015-04-01 09:00:33 N   365.00  10
4   2015-04-01 09:00:36 N   367.80  55
5   2015-04-01 09:00:41 N   365.00  10
6   2015-04-01 09:00:41 N   367.80  55

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