编写一个python脚本,在每天的给定时间生成一个时间戳(unix epoch值) [英] Write a python script to generate a timestamp ( unix epoch value) each day at a give time
问题描述
我想编写一个小型 python,它需要在每天下午 1 点的特定时间生成一个简单的精确时间戳(脚本将每天运行).我是这样写的:
from datetime import datetimenow = datetime.utcnow() # 当前时间then = datetime(1970,1,1) # 0 纪元时间ts = 现在 - 然后ts = ts.days * 24 * 3600 + ts.seconds打印 ts
这很好,但我想通过 now
作为我每天的 time_field.我该怎么做?
你可以使用time.mktime
函数:
如果您需要时区感知,请使用时区感知日期时间的 utctimetuple
方法和 time.gmtime
函数.
(编辑以显示如何为特定时间创建 datetime.datetime)
I want to write a small python which needs to generate a simple precise timestamp each day ( the script will be run each day) at a particular hour say 1pm. I wrote something like this:
from datetime import datetime
now = datetime.utcnow() # Current time
then = datetime(1970,1,1) # 0 epoch time
ts = now - then
ts = ts.days * 24 * 3600 + ts.seconds
print ts
This is good, but i want to pass now
for the time_field that i on daily basis. How do I do this?
You can use the time.mktime
function:
>>> import datetime
>>> import time
>>> dt = datetime.datetime.today().replace(hour=13, minute=0, second=0, microsecond=0)
>>> print(dt)
2016-04-06 13:00:00
>>> time.mktime(dt.timetuple())
1459944000.0
If you need to be timezone-aware, use a timezone-aware datetime's utctimetuple
method and the time.gmtime
function.
(edited to show how to create datetime.datetime for a specific time)
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