根据服务器 UTC 偏移量和用户 UTC 偏移量更改当前用户时区 [英] Changing current user timezone based on server UTC offset and user UTC offset

问题描述

我正在用 php 编写 Twitter 网络服务.当用户登录时，我收到此节点:

im writing a twitter web service in php. When a user signs in, i receive this node:

<utc_offset>-18000</utc_offset>

我必须更改脚本的时区以适应用户的实际时区.我为此找到的唯一 php 函数是:date_default_timezone_set($timezone_identifier) 但它不会让我使用 -18000 作为 $timezone_identifier 参数.

I have to change the script's timezone so that it adapts to the user's real timezone. The only php function i have found for this is: date_default_timezone_set($timezone_identifier) but it won't let me use -18000 as a the $timezone_identifier parameter.

那么，我如何根据两个值更改当前用户时区:服务器 UTC 偏移量和用户 UTC 偏移量

So, how can i change the current user timezone based on two values: Server UTC offset and User UTC offset

顺便说一句，这是我获取服务器 UTC 偏移值的方式:

BTW, this is how i'm getting the server UTC offset value:

$this_tz_str = date_default_timezone_get();
$this_tz = new DateTimeZone($this_tz_str);
$now = new DateTime("now", $this_tz);
$offset = $this_tz->getOffset($now);

有什么想法吗?谢谢！

推荐答案

获取当前服务器时间

date_default_timezone_set(date_default_timezone_get());
echo date('Y-m-d H:i:s', time());

欧洲/巴黎的输出(我的服务器设置；UTC+2)

Output for Europe/Paris (my server settings; UTC+2)

2011-04-12 20:39:43

通过偏移量获取用户的时间

To get user's time by offset

$user_offset = '-18000';
date_default_timezone_set('UTC');
$diff = "$user_offset seconds";
if ((substr($diff,0,1) != '+') && (substr($diff,0,1) != '-')) $diff = '+' . $diff;
$usertime = strtotime($diff, time());
echo date('Y-m-d H:i:s', $usertime);

输出 UTC-5(厄瓜多尔 -> 基多时间无夏令时)，php 时区标识符 'America/Guayaquil'.

Output UTC-5 (Ecuador -> Quito time NO DST), php timezone identifier 'America/Guayaquil'.

2011-04-12 13:39:43

PHP.net 手册:

PHP.net manual:

时区偏移量(以秒为单位).偏移量对于UTC以西的时区总是负数，对于 UTC 以东的人来说是总是积极的.(-43200 通过50400)

Timezone offset in seconds. The offset for timezones west of UTC is always negative, and for those east of UTC is always positive. (-43200 through 50400)

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