使用 tkinter Treeview 小部件显示目录内容 [英] Display directory content with tkinter Treeview widget

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本文介绍了使用 tkinter Treeview 小部件显示目录内容的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

目前我正在开发一个程序,它有自己的项目文件,里面有子文件,我想知道如何使用树视图小部件来显示项目文件中的所有子文件,任何想法?

At the moment I am working on a program that has its own project files and inside that are like sub-files and I want to know how to use the treeview widget to display all the sub-files inside the project file, Any Ideas?

提前致谢!

推荐答案

有一个 CPython 源代码中的示例 如何用目录的内容递归地填充树视图,这基本上是它的工作原理(我已经删除了事件绑定并将其包装在一个类以提高可读性):

There is an example in the source code of CPython of how to fill a Treeview recursively with the content of a directory, this is basically how it works (I have removed the event bindings and wrapped it in a class for better readability):

import os
import tkinter as tk
import tkinter.ttk as ttk

class App(tk.Frame):
    def __init__(self, master, path):
        tk.Frame.__init__(self, master)
        self.tree = ttk.Treeview(self)
        ysb = ttk.Scrollbar(self, orient='vertical', command=self.tree.yview)
        xsb = ttk.Scrollbar(self, orient='horizontal', command=self.tree.xview)
        self.tree.configure(yscroll=ysb.set, xscroll=xsb.set)
        self.tree.heading('#0', text=path, anchor='w')

        abspath = os.path.abspath(path)
        root_node = self.tree.insert('', 'end', text=abspath, open=True)
        self.process_directory(root_node, abspath)

        self.tree.grid(row=0, column=0)
        ysb.grid(row=0, column=1, sticky='ns')
        xsb.grid(row=1, column=0, sticky='ew')
        self.grid()

    def process_directory(self, parent, path):
        for p in os.listdir(path):
            abspath = os.path.join(path, p)
            isdir = os.path.isdir(abspath)
            oid = self.tree.insert(parent, 'end', text=p, open=False)
            if isdir:
                self.process_directory(oid, abspath)

root = tk.Tk()
path_to_my_project = # ...
app = App(root, path=path_to_my_project)
app.mainloop()

<小时>

更新: 正如@ArtOfWarfare 所提到的,可以使用 <<TreeviewOpen>> 事件延迟填充树.为了模拟关闭的节点,我使用了一个在打开目录时删除的空子项:


Update: As @ArtOfWarfare mentions, it is possible to lazy populate the tree using the <<TreeviewOpen>> event. To simulate the closed nodes, I've used an empty child item that is removed when a directory is opened:

import os
import tkinter as tk
import tkinter.ttk as ttk


class App(object):
    def __init__(self, master, path):
        self.nodes = dict()
        frame = tk.Frame(master)
        self.tree = ttk.Treeview(frame)
        ysb = ttk.Scrollbar(frame, orient='vertical', command=self.tree.yview)
        xsb = ttk.Scrollbar(frame, orient='horizontal', command=self.tree.xview)
        self.tree.configure(yscroll=ysb.set, xscroll=xsb.set)
        self.tree.heading('#0', text='Project tree', anchor='w')

        self.tree.grid()
        ysb.grid(row=0, column=1, sticky='ns')
        xsb.grid(row=1, column=0, sticky='ew')
        frame.grid()

        abspath = os.path.abspath(path)
        self.insert_node('', abspath, abspath)
        self.tree.bind('<<TreeviewOpen>>', self.open_node)

    def insert_node(self, parent, text, abspath):
        node = self.tree.insert(parent, 'end', text=text, open=False)
        if os.path.isdir(abspath):
            self.nodes[node] = abspath
            self.tree.insert(node, 'end')

    def open_node(self, event):
        node = self.tree.focus()
        abspath = self.nodes.pop(node, None)
        if abspath:
            self.tree.delete(self.tree.get_children(node))
            for p in os.listdir(abspath):
                self.insert_node(node, p, os.path.join(abspath, p))


if __name__ == '__main__':
    root = tk.Tk()
    app = App(root, path='.')
    root.mainloop()

这篇关于使用 tkinter Treeview 小部件显示目录内容的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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