通过Tkinter中的按钮将参数传递给函数，循环中的starnge行为 [英] Passing argument to a function via a Button in Tkinter, starnge behaviour in loop

问题描述

我目前正在尝试修复 Python 书籍Python 下一步"中作者尚未修复的错误并在代码中留下评论:稍后修复"

I am currently trying to fix a bug in the python book "Python next step" which the author has not fixed and left a comment in the code : "Fix later"

我的第一个解决方案失败了，但第二个解决方案通过删除循环而成功.问题是我不知道为什么第一个解决方案失败了！

My first solution failed but the second solution succeeded by removing the loop. Problem is I cannot figure out why the first solution fails!

解决方案 1:

当用户使用循环点击 Tkinter 中制作的计算器中的按钮时，Button 对象和名为 click thecalculator 的函数只是从 lambda 参数打印一个大写的 C.代码注释为有问题的鳕鱼附近的人字形，在我所说的点上.

When a user clicks the button in the calculator made in Tkinter using a loop, Button object and a function called click the calculator just prints a capital C from the lambda argument.The code is commented by chevrons near the offending cod, at the points I am talking about.

解决方案 2:

删除生成按钮的循环并重复手动编码每个按钮！这很有效，正如 Brian kernighan 建议的那样:在使其高效之前先让它工作！

Remove the loop that generated buttons and hand code each button repetitively!This works and as Brian kernighan suggest: getting it to work first before making it efficient!

代码:

# myCalculator3_final.py

from Tkinter import *
from decimal import *

# key press function:
def click(key):
        display.insert(END, key)


##### main:
window = Tk()
window.title("MyCalculator")

# create top_row frame
top_row = Frame(window)
top_row.grid(row=0, column=0, columnspan=2, sticky=N)

# use Entry widget for an editable display
display = Entry(top_row, width=45, bg="light green")
display.grid()

# create num_pad_frame
num_pad = Frame(window)
num_pad.grid(row=1, column=0, sticky=W)

# This method of passing an argument to click work! Loop removed and buttons hand code
#>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
#-------------------------------------------------------------------------
# create num_pad buttons passing an argument to the command function click
#-------------------------------------------------------------------------   
seven = Button(num_pad, text="7", width=5, command=lambda :click("7"))
seven.grid(row=0,column=0)
eight = Button(num_pad, text="8", width=5, command=lambda :click("8"))
eight.grid(row=0,column=1)
nine= Button(num_pad, text="9", width=5, command=lambda :click("9"))
nine.grid(row=0,column=2)
four= Button(num_pad, text="4", width=5, command=lambda :click("4"))
four.grid(row=1,column=0)
five= Button(num_pad, text="5", width=5, command=lambda :click("5"))
five.grid(row=1,column=1)
six= Button(num_pad, text="6", width=5, command=lambda :click("6"))
six.grid(row=1,column=2)
one= Button(num_pad, text="1", width=5, command=lambda :click("1"))
one.grid(row=2,column=0)
two= Button(num_pad, text="2", width=5, command=lambda :click("2"))
two.grid(row=2,column=1)
three= Button(num_pad, text="3", width=5, command=lambda :click("3"))
three.grid(row=2,column=2)
zero= Button(num_pad, text="0", width=5, command=lambda :click("0"))
zero.grid(row=2,column=0)
#---------------------------------------------------------------------------   



# calculate the row, column for button

# create operator_frame
operator = Frame(window)
operator.grid(row=1, column=1, sticky=E)

operator_list = [
'*', '/',  
'+', '-',
'(', ')',
'C' ]

# The authors code and I have added  the same lambda function as above but 
#it just prints out capital C
#>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
r = 0
c = 0
for btn_text in operator_list:
    Button(operator, text=btn_text, width=5, command=lambda: click(btn_text)).grid(row=r,column=c)
    c = c+1
    if c > 1:
        c = 0
        r = r+1


##### Run mainloop
window.mainloop()

问题:

为什么用于单击传递参数的 lambda 调用方法在循环中不起作用并且只显示一个 C 但如果我删除循环它就可以工作！

Why does the lambda calling method to click passing an argument not work in the loop and only display a C but if I remove the loop it works!

推荐答案

在这一行:

Button(operator, text=btn_text, width=5, command=lambda: click(btn_text)).grid(row=r,column=c)

lambda 中 btn_text 的值不会被其当前值冻结.相反，当 btn_text 在循环的下一次迭代中发生变化时，它在 lambda 中求值的值也会发生变化.这意味着您的所有按钮实际上都有一个 click('C') 命令，因为 'C' 是 btn_text 的最终值.

The value of btn_text within the lambda will not become frozen with its current value. Instead, when btn_text changes in the next iteration of the loop, the value it evaluates to in the lambda will also change. This means that all of your Buttons effectively have a click('C') command, since 'C' is the final value of btn_text.

你可以这样做:

command=lambda text=btn_text: click(text)

或

command=(lambda text: lambda: click(text))(btn_text)

text 会捕获btn_text 的当前值，之后不会改变.您的命令将使用正确的参数调用.

text will capture the current value of btn_text, and not change afterwards. Your commands will get called with the proper arguments.

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