当用户单击按钮时如何打开一个新窗口? [英] How can I open a new window when the user clicks the button?
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问题描述
当用户单击按钮(仍需要创建)时,我将如何创建新窗口?我拿出了一些代码来缩短它.我需要创建一个按钮,当他们点击该按钮时,会打开一个新窗口.我还没有创建按钮,因为按钮必须链接到新窗口.请帮忙
How would I create a new window when the user clicks a button (still needs creating)? I have took some code out to make this shorter. I need a button creating and when they hit that button, a new window opens. I haven't created the button because the button has to be linked to the new window. Please help
My imports...
class App:
def __init__(self, master):
self.master = master
# call start to initialize to create the UI elemets
self.start()
def start(self):
self.master.title("E-mail Extranalyser")
self.now = datetime.datetime.now()
tkinter.Label(
self.master, text=label01).grid(row=0, column=0, sticky=tkinter.W)
# CREATE A TEXTBOX
self.filelocation = tkinter.Entry(self.master)
self.filelocation["width"] = 60
self.filelocation.focus_set()
self.filelocation.grid(row=0, column=1)
# CREATE A BUTTON WITH "ASK TO OPEN A FILE"
# see: def browse_file(self)
self.open_file = tkinter.Button(
self.master, text="Browse...", command=self.browse_file)
# put it beside the filelocation textbox
self.open_file.grid(row=0, column=2)
# now for a button
self.submit = tkinter.Button(
self.master, text="Execute!", command=self.start_processing,
fg="red")
self.submit.grid(row=13, column=1, sticky=tkinter.W)
def start_processing(self):
#code here
def browse_file(self):
# put the result in self.filename
self.filename = filedialog.askopenfilename(title="Open a file...")
# this will set the text of the self.filelocation
self.filelocation.insert(0, self.filename)
root = tkinter.Tk()
app = App(root)
root.mainloop()
推荐答案
使用 Toplevel 打开一个新的.修改您的代码,如下所示.
Use a Toplevel to open a new one. Modify your code as shown below.
self.NewWindow = tkinter.Button(self.master,
text="New Window",
command=self.CreateNewWindow)
def CreateNewWindow(self):
self.top = tkinter.Toplevel()
self.top.title("title")
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