tkinter 显示当前标签，删除上一个 [英] tkinter Display current label,deleting the previous

问题描述

我正在尝试一个程序，它将显示在输入框中输入的相应名称的标签.问题:它重叠并显示标签，而不是消失之前的条目标签.

I am trying a program,which will display label for the respective name entered in the Entry box. Problem: It overlaps and displays the label,instead of disappearing the previous entry label.

我的编码:

import Tkinter as tki
class App(object):
     def __init__(self,root):
         self.root = root

         self.txt_frm = tki.Frame(self.root, width=900, height=900)
         self.txt_frm.pack(fill="both", expand=True)
         button3 = tki.Button(self.txt_frm,text="CLICK 1", command = self.retrieve_inpu)
         button3.grid(column=0,row=2)
         self.entry = tki.Entry(self.txt_frm) 
         self.entry.grid(column=1,row=0)

     def retrieve_inpu(self):
        ent = self.entry.get()
        label = tki.Label(self.txt_frm,text=ent)
        label.grid(column=0,row=3)

root = tki.Tk()
app = App(root)
root.mainloop()

请帮我删除之前的条目并显示标签.

Please help me to disappear the previous entry and display the label.

推荐答案

不是每次按下按钮时都创建一个新标签，只需更改标签的文本即可.我已经编辑了您的代码来演示:

Instead of creating a new label every time the button is pressed, just change the text of the label. I have edited your code to demonstrate:

import Tkinter as tki
class App(object):
     def __init__(self,root):
         self.root = root

         self.txt_frm = tki.Frame(self.root, width=900, height=900)
         self.txt_frm.pack(fill="both", expand=True)
         button3 = tki.Button(self.txt_frm,text="CLICK 1", command = self.retrieve_inpu)
         button3.grid(column=0,row=2)
         self.entry = tki.Entry(self.txt_frm)
         self.entry.grid(column=1,row=0)

         #create label in init
         self.label = tki.Label(self.txt_frm)
         self.label.grid(column=0,row=3)

     def retrieve_inpu(self):
        ent = self.entry.get()

        #treat label properties as a dict for tkinter
        #assign a new text value
        self.label['text'] = ent


root = tki.Tk()
app = App(root)
root.mainloop()

当然，如果您希望每次都创建一个新标签，请先销毁旧标签.这是对相同代码的不同修改.

Of course, if you prefer to create a new label every time, destroy the old one first. This is a different modification of the same code.

import Tkinter as tki
class App(object):
     def __init__(self,root):
         self.root = root

         self.txt_frm = tki.Frame(self.root, width=900, height=900)
         self.txt_frm.pack(fill="both", expand=True)
         button3 = tki.Button(self.txt_frm,text="CLICK 1", command = self.retrieve_inpu)
         button3.grid(column=0,row=2)
         self.entry = tki.Entry(self.txt_frm)
         self.entry.grid(column=1,row=0)

         #place holder for label variable
         self.label = None

     def retrieve_inpu(self):
        ent = self.entry.get()

        #destroy the widget if it has been created
        #you will have a bunch of orphans if you don't
        if self.label:
            self.label.destroy()

        self.label = tki.Label(self.txt_frm,text=ent)
        self.label.grid(column=0,row=3)

root = tki.Tk()
app = App(root)
root.mainloop()

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