在多维列表中搜索元素不起作用.任何线索 [英] Search of Element inside a multi-dimensional List Not Working. Any Clue

问题描述

我正在尝试在多维列表中搜索元素，但它不起作用.我的搜索有什么问题吗??下面是简单的代码，我尝试使用 'in' 和 'any' 进行搜索，但没有用.

I am trying to search for an element inside a multi-dimensional list, but its not working. Anything wrong in my search ?? Below is the simple code and I tried searching using 'in' and 'any' but didnt work..

list1 = []
list1.append([['hello'], ['blue'], ['bla']])

print list1

list1.append([['hello'], ['blue'], ['bla']])
print list1

#if 'hello' in list1:
if any('hello' in x for x in list1):
    print "Found Hello"
else:
    print "Not Found Hello"

猜猜我在做什么错误??请分享您的意见/意见.

Any guess whats the error I am doing ?? Kindly share in your inputs/comments.

感谢 Adv ！维摩

推荐答案

如果 list1 应该是一个列表列表，那么问题是你将一个列表附加到 list1code>，在这种情况下，使用 extend 代替.

If list1 should be a list of lists, then the problem is that you are appending a list to list1, in this case, use extend instead.

如果你想在一个嵌套列表(任意数量级)中搜索一个项目，你可以使用这个函数

If you want to search a item in a nested list (any number of levels), you can use this function

def in_nested_list(item, x):
    if not isinstance(x, list):
        return x == item
    else:
        return any(in_nested_list(item, ix) for ix in x)

list1 = []
list1.append([['hello'], ['blue'], ['bla']])

print list1

list1.append([['hello'], ['blue'], ['bla']])
print list1

#if 'hello' in list1:
if in_nested_list('hello', list1):
    print "Found Hello"
else:
    print "Not Found Hello"

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