Python:Tkinter:动态创建标签 [英] Python: Tkinter :Dynamically Create Label

问题描述

我正在尝试动态创建标签，但语法无效.你能帮我看看我缺少什么或任何其他选择

I am trying to create Label Dynamically , I am getting invalid Syntax. Can you please help me what i am missing or any alternative

      crsr = cnxn.execute(query)
        row_num=2
        column_num=0
        Variable_Number=1
        for row in crsr.fetchall():

            test='Column_Label'+str(Variable_Number)+' = tk.Label(frame,text="'+row[0]+'")'



#proper Indentation availabe in code        test1='Column_Label'+str(Variable_Number)+'.grid(row='+str(row_num)+',column='+str(column_num)+')'
            eval(test+';'+test1)
    #        eval(test1)
            row_num+=1
            column_num+=1
        root.update_idletasks()

推荐答案

你不应该使用 exec.如果您想将计算出的名称与循环中的小部件相关联，请使用字典:

You should not be using exec. If you want to associate a computed name with a widget in a loop, use a dictionary:

labels = {}
varnum = 0
for row in crsr.fetchall():
    name=f"label#{varnum}"
    labels[name] = tk.Label(frame, text=str(row[0]))
    labels[name].grid(row=row_num, column=column_num
    varnum += 1
    row_num+=1
    column_num+=1

如果您真的不关心名称是什么，您可以将小部件存储在列表而不是字典中，然后使用整数索引引用它们(例如:labels[0]、labels[1] 等).

If you don't really care what the name is, you can store the widgets in a list rather than a dictionary, and then reference them using an integer index (eg: labels[0], labels[1], etc).

这篇关于Python:Tkinter:动态创建标签的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！