在 c 语句中计算令牌 [英] Calculating tokens in c statement

问题描述

以下 C 语句中的标记数.

The number of tokens in the following C statement.

printf("i = %d, &i = %x", i, &i);

我认为这里有 12 个令牌.但我的回答是错误的.

I think there are 12 tokens here. But my answer is wrong.

谁能告诉我如何在上面的 C 语句中找到标记?

Can anybody tell me how to find the tokens in the above C statement?

PS:我知道标记是编译器不会分解为组件元素的源程序文本.

PS: I know that a token is source-program text that the compiler does not break down into component elements.

推荐答案

据我了解的 C 代码解析，token 是(共 10 个):

As far as I understand C code parsing, the tokens are (10 in total):

printf
(
"i = %d, &i = %x"
,
i
,
&
i
)
;

我不计算空格，它通常没有意义，仅用作其他标记之间的分隔符，而且我不会将字符串文字分解为多个部分，因为它是其自身的一个完整实体.

I don't count white space, it's generally meaningless and only serves as a separator between other tokens, and I don't break down the string literal into pieces, because it's an integral entity of its own.

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