PHP字符串嵌套数组 [英] PHP string to nested array
本文介绍了PHP字符串嵌套数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我需要一个字符串从LDAP查询转换。我查询我的Active Directory服务器上的用户帐户。这是我拉的字符串。
CN =菲尔·罗伯逊,OU =用户,OU =鸭司令,OU =部门和放大器;建筑,DC = OCSDtest,DC =本地
我想它转换为一个数组,看起来像这样
$数组['本地'] ['OCtest'] ['部和放大器;建筑'] ['鸭司令'] ['用户'] ['菲尔·罗伯逊'] = 1;
不是
$阵列([1] =>'的地方,[2] =>'OCtest,[3] ='出发',[4] ='鸭司令 [5] ='用户');
到目前为止,我有
举例code ---
$ dnn2 = ldap_explode_dn(CN =菲尔·罗伯逊,OU =用户,OU =鸭司令,OU =部门和放大器;建筑,DC = OCSDtest,DC =本地,1) ;
未设置($ dnn2 ['伯爵']);
回声< pre>中;
的print_r(array_reverse(dnn2 $));
我是什么需要?
解决方案
$ dnn2 = ldap_explode_dn(CN =菲尔·罗伯逊,OU =用户,OU =鸭司令,OU =部门和放大器;建筑,DC = OCSDtest,DC =本地,1);
未设置($ dnn2 ['伯爵']);
$结果= NULL;
$ REF =&放大器; $结果;
的foreach(array_reverse($ dnn2)为$ DN){
$ REF =阵列($ DN => NULL);
$ REF =&放大器; $文献[$ DN];
}
的print_r($结果);
I need to convert a string from an ldap query. I am querying my Active Directory server for user accounts. This is the string that I pulled.
"CN=Phil Robertson,OU=Users,OU=Duck Commander,OU=Department & Buildings,DC=OCSDtest,DC=local"
I would want it converted to an array that looks like this
$array['local']['OCtest']['Department & Buildings']['Duck Commander']['Users']['Phil Robertson']=1;
NOT
$array( [1]=>'local,[2]=>'OCtest',[3]='Depart',[4]='Duck Commander',[5]='Users');
So far I have
Example code ---
$dnn2 = ldap_explode_dn("CN=Phil Robertson,OU=Users,OU=Duck Commander,OU=Department & Buildings,DC=OCSDtest,DC=local",1);
unset($dnn2['count']);
echo "<pre>";
print_r(array_reverse($dnn2));
What am I needing?
解决方案
$dnn2 = ldap_explode_dn("CN=Phil Robertson,OU=Users,OU=Duck Commander,OU=Department & Buildings,DC=OCSDtest,DC=local",1);
unset($dnn2['count']);
$result = null;
$ref =& $result;
foreach (array_reverse($dnn2) as $dn) {
$ref = array($dn => null);
$ref =& $ref[$dn];
}
print_r($result);
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