什么是存储在单元格中的数据，并存储为双MATLAB中的数据之间的区别？ [英] What is the difference between the data stored in a cell and the data stored as double in MATLAB?

问题描述

我有两个变量，谁长得一模一样给我，但一个是＆LT;双＆GT; ，另一个是＆LT;电池＆gt; 。在code看来，它们是由 cell2mat 转换。我的理解是数据存储的问题，但我只是不明白的区别和细胞和双击这一点。

I have two variables who look exactly the same to me, but one is <double> and the other is <cell>. In the code it seems that they are converted by cell2mat. I understand it is a question of data storage but I just don't see the difference and the definition of cell and double for this.

推荐答案

添加到NRZ的回答，值得注意的是，存储单元阵列时，还有一个额外的内存开销。例如，请考虑以下code：

Adding to nrz's answer, it is noteworthy that there is an additional memory overhead when storing cell arrays. For instance, consider the following code:

A = 1:5
B = {A}
C = num2cell(A)
whos

产生以下输出：

A =
     1     2     3     4     5


B =    
    [1x5 double]


C = 
    [1]    [2]    [3]    [4]    [5]

  Name      Size            Bytes  Class     Attributes    
  A         1x5                40  double              
  B         1x1               152  cell                
  C         1x5               600  cell                

• 你可以从第一行看到，双打基本1 * 5载体 A 需要在内存中40字节（每个双重需要8个字节）。


• 第二行显示，只是包装 A 用单细胞产生 B 增加了额外的112个字节。这是在MATLAB单个小区的开销。


• 第三行确认，因为 C 包含5个细胞，并采用（112 + 8）×5 = 600个字节。


• As you can see from the first line, the basic 1-by-5 vector A of doubles takes 40 bytes in memory (each double takes 8 bytes).
• The second line shows that just wrapping A with a single cell to produce B adds extra 112 bytes. That's the overhead of a single cell in MATLAB.
• The third line confirms that, because C contains 5 cells and takes (112+8)×5 = 600 bytes.

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