从字符串中修剪多个换行符和多个空格? [英] Trim multiple line breaks and multiple spaces off a string?

问题描述

如何修剪多个换行符?

例如

$text ="similique sunt in culpa qui officia


deserunt mollitia animi, id est laborum et dolorum fuga. 



Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore
"

我试过这个 answer 但它不适用于上述情况我认为，

I tried with this answer but it does not work for the case above I think,

$text = preg_replace("/\n+/","\n",trim($text));

我想得到的答案是，

$text ="similique sunt in culpa qui officia

    deserunt mollitia animi, id est laborum et dolorum fuga. 

    Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore
    "

只接受单个换行符.

我还想同时修剪多个空白，如果我在下面这样做，我无法保存任何换行符！

Also I want to trim multiple white space at the same time, if I do this below, I can't save any line break!

$text = preg_replace('/\s\s+/', ' ', trim($text));

我怎样才能在正则表达式中做这两件事?

How can I do both thing in line regex?

推荐答案

在这种情况下，您的换行符是 \r\n，而不是 \n:

Your line breaks in this case are \r\n, not \n:

$text = preg_replace("/(\r\n){3,}/","\r\n\r\n",trim($text));

意思是每次找到 3 个或更多换行符时，用 2 个换行符替换它们".

That says "every time 3 or more line breaks are found, replace them with 2 line breaks".

空格:

$text = preg_replace("/ +/", " ", $text);
//If you want to get rid of the extra space at the start of the line:
$text = preg_replace("/^ +/", "", $text);

演示:http://codepad.org/PmDE6cDm

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