XQuery 在单个 SQL 更新命令中添加或替换属性 [英] XQuery adding or replacing attribute in single SQL update command

查看:31
本文介绍了XQuery 在单个 SQL 更新命令中添加或替换属性的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个带有 XML 列的表,如果属性已经存在,我想更新 xml 以插入属性或更改属性值.

I have a Table with an XML column, I want to update the xml to insert attribute or to change the attribute value if the attribute already exists.

假设起始 xml 是:</>

Let's say the starting xml is: < d />

插入:

UPDATE Table 
set XmlCol.modify('insert attribute att {"1"} into /d[1]')

变化:

UPDATE Table
set XmlCol.modify('replace value of /d[1]/@att with "1"')

如果属性已经存在,插入将失败,如果属性不存在,替换将失败.我曾尝试使用 'if',但我认为它行不通,出现错误:XQuery [modify()]:'attribute' 附近的语法错误,预期为 'else'."

insert will fail if the attribute already exists, replace will fail if the attribute doesn't exists. I have tried to use 'if' but I don't think it can work, there error I get: "XQuery [modify()]: Syntax error near 'attribute', expected 'else'."

IF 尝试

UPDATE Table 
set XmlCol.modify('if empty(/d[1]/@att) 
                   then insert attribute att {"1"} into /d[1]
                   else replace value of /d[1]/@att with "1"')

目前我选择 xml 到一个变量中,然后使用 T-SQL 修改它,然后用新的 xml 更新列,这需要我锁定事务中的行,并且对于数据库来说可能更昂贵.

Currently I select the xml into a variable and then modify it using T-SQL and then updating the column with new xml, this requires me to lock the row in a transaction and is probably more expensive for the DB.

推荐答案

据我所知,单条语句无法做到这一点.您可以使用 exist() 方法通过两个更新语句来完成此操作.

From what I can tell, you can't do this with single statement. You can use the exist() method to accomplish that with two update statements.

DECLARE @TestTable TABLE
(
    Id int,
    XmlCol xml
);

INSERT INTO @TestTable (Id, XmlCol)
VALUES
    (1, '<d att="1" />'),
    (2, '<d />'),
    (3, '<d att="3" />');

SELECT * FROM @TestTable;

UPDATE @TestTable
SET XmlCol.modify('replace value of /d[1]/@att with "1"')
WHERE XmlCol.exist('(/d[1])[not(empty(@att))]') = 1;

UPDATE @TestTable
SET XmlCol.modify('insert attribute att {"1"} into /d[1]')
WHERE XmlCol.exist('(/d[1])[empty(@att)]') = 1;

SELECT * FROM @TestTable;

最终选择的输出是:

Id          XmlCol
----------- -------------------
1           <d att="1" />
2           <d att="1" />
3           <d att="1" />

这篇关于XQuery 在单个 SQL 更新命令中添加或替换属性的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆