JavaScript中，排序ARRAY1基于arry2 [英] javascript, sort array1 based on arry2

问题描述

我没有在JavaScript如下：

I did the following in javascript:

var arr1 =[1,2,3,4];
var arr2 =["ac", "bc", "ad", "e"];
var result = arr1 .sort(function(i, j){return arr2[i].localeCompare(arr2[j])})
document.write(result );

我的意图是要排序数组1 根据数组2 。我期待的结果是 1,3,2,4 ，但事实证明这是 2,1,3,4 任何人都可以找出原因？谢谢

my intention was to sort array1 based on array2. I was expecting the result to be 1,3,2,4, but as it turns out it is 2,1,3,4 can anyone figure out why? Thanks

推荐答案

数组是0索引，让你的排序功能启动第二和通过第五一路进行比较;忽略第一元件和事实，即不存在第五元素

Arrays are 0-indexed, so your sort function starts comparing with the second and all the way through the fifth; ignoring the first element and the fact that there is no 5th element.

插入-1排序函数应该修复它：

Inserting a -1 in the sort function should fix it:

arr1.sort(function(i, j){
    return arr2[i-1].localeCompare(arr2[j-1])
});

的结果确实 [1，3，2，4]

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