从 python 元组中弹出/删除项目 [英] pop/remove items out of a python tuple

问题描述

我不确定我是否能说清楚，但会尝试.

I am not sure if I can make myself clear but will try.

我在 python 中有一个元组，我按如下方式进行(见下面的代码).在检查过程中，我维护了一个计数器(我们称之为n")和满足特定条件的弹出"项目.

I have a tuple in python which I go through as follows (see code below). While going through it, I maintain a counter (let's call it 'n') and 'pop' items that meet a certain condition.

当然，一旦我弹出第一个项目，编号就会出错，我怎样才能更优雅地做我想做的事，同时只删除某个元组的某些条目?

Now of course once I pop the first item, the numbering all goes wrong, how can I do what I want to do more elegantly while removing only certain entries of a tuple on the fly?

for x in tupleX:
  n=0
  if (condition):
     tupleX.pop(n)
  n=n+1

推荐答案

好的，我想出了一个粗略的方法.

ok I figured out a crude way of doing it.

当条件在列表中满足时，我将n"值存储在 for 循环中(我们称之为 delList)然后执行以下操作:

I store the "n" value in the for loop when condition is satisfied in a list (lets call it delList) then do the following:

    for ii in sorted(delList, reverse=True):
    tupleX.pop(ii)

也欢迎任何其他建议.

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