将字符串转换为元组并添加到元组 [英] Converting string to tuple and adding to tuple

问题描述

我有一个这样的配置文件.

[rects]rect1=(2,2,10,10)rect2=(12,8,2,10)

我需要遍历这些值并将它们转换为元组.然后我需要制作一个元组的元组，如

((2,2,10,10), (12,8,2,10))

解决方案

要将字符串转换为整数元组(我假设这是您想要的)，您可以使用这样的正则表达式:

x = "(1,2,3)"t = tuple(int(v) for v in re.findall("[0-9]+", x))

您可以使用例如 configparser 来解析配置文件.>

I have a config file like this.

[rects]
rect1=(2,2,10,10)
rect2=(12,8,2,10)

I need to loop through the values and convert them to tuples. I then need to make a tuple of the tuples like

((2,2,10,10), (12,8,2,10))

解决方案

To turn the strings into tuples of ints (which is, I assume, what you want), you can use a regex like this:

x = "(1,2,3)"
t = tuple(int(v) for v in re.findall("[0-9]+", x))

And you can use, say, configparser to parse the config file.

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