如何从元组中删除最后一个逗号? [英] How to remove the last comma from tuples?
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问题描述
如何从列表中的每个元组中删除逗号.
我想从这样的列表中创建一个元组列表:
How can I remove the comma from each tuple in the list.
I want to make a list of tuples from one list like this:
l = [1,2,3,5,4]
l1 = [ ]
l2 = [ ]
for i in l:
l1.append (i)
t = tuple(l1)
l2.append(t)
l1 = []
print l2
预期结果:
[(1), (2), (3), (5), (4)]
真实结果:
[(1,), (2,), (3,), (5,), (4,)]
推荐答案
如果您只想显示列表中每个元组的第一个元素(不带逗号),您始终可以使用以下内容手动格式化输出:
If you only want the first element of each tuple in the list displayed (without a comma), you can always manually format the output by using something like this:
l = [1, 2, 3, 5, 4]
l1 = []
l2 = []
for i in l:
l1.append(i)
t = tuple(l1)
l2.append(t)
l1 = []
print '[' + ', '.join('({})'.format(t[0]) for t in l2) + ']'
输出:
[(1), (2), (3), (5), (4)]
顺便说一句,您也可以将 l2
的构造缩短为:
BTW, you could also shorten the construction of l2
to just this:
l2 = [tuple([value]) for value in l]
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