使用 Turtle 的井字游戏 [英] Tic Tac Toe Game using Turtle
问题描述
这是用于 Python 中的额外学分分配.我已经完成了大部分，直到最后一部分我必须确定选择的 tictactoe 框的区域.
This is for an extra credit assignment in Python. I've finished most until the last part where I have to determine the area of the tictactoe box chosen.
更新，我只能检测对角线框，用于组合下面的两个代码回复.我可以检测到这 3 个框，但其余的仍然显示为无，并且大多数逻辑都与循环一起使用，因此我可以理解我哪里出错了.
Update, I can only detect diagonal boxes, used from combining both code reply's below. I can detect those 3 boxes but the rest still show as none and most logic is used with loop so I can understand where I am going wrong.
import turtle
from time import sleep
import sys
CURSOR_SIZE = 20
SQUARE_SIZE = 99
FONT_SIZE = 40
FONT = ('Arial', FONT_SIZE, 'bold')
BOXES = {}
# TRACK BOX
pen = turtle.Turtle()
pen.penup()
def mouse(x, y):
print('|--------------X={0} Y={1}--------------|'.format(x, y))
for key in BOXES:
minx, miny, maxx, maxy = BOXES[key]
print(key, BOXES[key])
if (minx <= x <= maxx) and (miny <= y <= maxy):
print("Found", key)
return key
print('None')
return None # Not found.
class TicTacToe:
global BOXES
def __init__(self):
# CREATES 2D LIST FOR INTERROGATION
self.board = [['?'] * 3 for i in range(3)]
def minmax(self, points):
""" Find extreme x and y values in a list of 2-D coordinates. """
minx, miny, maxx, maxy = points[0][0], points[0][1], points[0][0], points[0][1]
for x, y in points[1:]:
if x < minx:
minx = x
if y < minx:
miny = y
if x > maxx:
maxx = x
if y > maxy:
maxy = y
return minx, miny, maxx, maxy
def drawBoard(self):
##############################################
turtle.shape('square')
turtle.shapesize(SQUARE_SIZE * 3 / CURSOR_SIZE)
turtle.color('black')
turtle.stamp()
turtle.hideturtle()
##############################################
for j in range(3):
for i in range(3):
# CREATES SHAPE AND STORES IN PLACEHOLDER
turtle.shape('square')
box = turtle.shape('square')
# CREATES SHAPE SIZE AND STORES IN PLACEHOLDER
turtle.shapesize(SQUARE_SIZE / CURSOR_SIZE)
boxsize = turtle.shapesize()
# CREATES SHAPE COLOR
turtle.color('white')
turtle.penup()
# CREATES SHAPE POS AND STORES IN PLACEHOLDER
turtle.goto(i * (SQUARE_SIZE + 2) - (SQUARE_SIZE + 2), j * (SQUARE_SIZE + 2) - (SQUARE_SIZE + 2))
boxpos = turtle.pos()
mypos = []
pen.goto(boxpos[0]-50,boxpos[1]+50)
##############################################
for line in range(0, 4):
pen.forward(SQUARE_SIZE)
pen.right(90)
mypos.append(pen.pos())
turtle.showturtle()
turtle.stamp()
##############################################
a = mypos[0]
b = mypos[1]
c = mypos[2]
d = mypos[3]
self.board[j][i] = [a, b, c, d]
##############################################
BOXES['BOX01'] = self.minmax(self.board[0][0])
BOXES['BOX02'] = self.minmax(self.board[0][1])
BOXES['BOX03'] = self.minmax(self.board[0][2])
##############################################
BOXES['BOX11'] = self.minmax(self.board[1][0])
BOXES['BOX12'] = self.minmax(self.board[1][1])
BOXES['BOX13'] = self.minmax(self.board[1][2])
##############################################
BOXES['BOX21'] = self.minmax(self.board[2][0])
BOXES['BOX22'] = self.minmax(self.board[2][1])
BOXES['BOX23'] = self.minmax(self.board[2][2])
##############################################
turtle.onscreenclick(mouse)
turtle.setup(800, 600)
wn = turtle.Screen()
z = TicTacToe()
z.drawBoard()
turtle.mainloop()
推荐答案
我相信您因为没有充分利用 Python 海龟而使问题变得比必要的困难.当点击屏幕时不要试图在棋盘内找到一个方块，而是让棋盘的方块本身成为响应鼠标点击的海龟.那么就没有什么需要弄清楚的，位置方面.
I believe you're making the problem harder than necessary by not taking full advantage of Python turtle. Instead of trying to find a square within the board when clicking on the screen, make the squares of the board themselves turtles that respond to mouse clicks. Then there's nothing to figure out, position-wise.
这是绘制板的重新实现，允许您单击它，将单击的部分交替设置为X"或O":
Here's a reimplementation that draws a board, allows you to click on it, alternately sets the clicked sections to 'X' or 'O':
from turtle import Turtle, Screen
CURSOR_SIZE = 20
SQUARE_SIZE = 50
FONT_SIZE = 40
FONT = ('Arial', FONT_SIZE, 'bold')
class TicTacToe:
def __init__(self):
self.board = [['?'] * 3 for i in range(3)] # so you can interrogate squares later
self.turn = 'X'
def drawBoard(self):
background = Turtle('square')
background.shapesize(SQUARE_SIZE * 3 / CURSOR_SIZE)
background.color('black')
background.stamp()
background.hideturtle()
for j in range(3):
for i in range(3):
box = Turtle('square', visible=False)
box.shapesize(SQUARE_SIZE / CURSOR_SIZE)
box.color('white')
box.penup()
box.goto(i * (SQUARE_SIZE + 2) - (SQUARE_SIZE + 2), j * (SQUARE_SIZE + 2) - (SQUARE_SIZE + 2))
box.showturtle()
box.stamp() # blank out background behind turtle (for later)
self.board[j][i] = box
box.onclick(lambda x, y, box=box, i=i, j=j: self.mouse(box, i, j))
def mouse(self, box, i, j):
box.onclick(None) # disable further moves on this square
# replace square/turtle with (written) X or O
box.hideturtle()
box.color('black')
box.sety(box.ycor() - FONT_SIZE / 2)
box.write(self.turn, align='center', font=FONT)
self.board[j][i] = self.turn # record move
self.turn = ['X', 'O'][self.turn == 'X'] # switch turns
screen = Screen()
game = TicTacToe()
game.drawBoard()
screen.mainloop()
您可以使用 board 进行评分，或者实现智能电脑播放器，或者您想要的任何东西.
You can use board to do scoring, or implement a smart computer player, or whatever you desire.
这篇关于使用 Turtle 的井字游戏的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
