提示用户在 Python 中输入的问题 [英] Problems prompting user for input in Python

问题描述

import sys
import turtle
t=turtle.Pen
def what_to_draw():
    print ("What to do you want to see a sketch of that may or may not be colored?")
what_to_draw=sys.stdin.readline()
if what_to_draw=="flower/n":
    t.forward(90)
elif():
    print ("What you typed isn't in the code. Try putting a letter or letters to lowercase or uppercase. If that doesn't work, what you typed has not been set to make something happen")

我在上面输入了这段代码.它在 python shell 中说花"没有定义.有人可以帮我解决这个问题吗?

I typed in this code above. It says in the python shell "flower" isn't defined. Can someone figure this out for me?

推荐答案

您的几行代码存在某种错误:

Several lines of your code have errors of some sort:

t=turtle.Pen 应该是:t = turtle.Pen()

你应该避免使用同名的函数和变量

You should avoid functions and variables with the same name

def what_to_draw():
    ...
    what_to_draw = sys.stdin.readline()

使用 rstrip() 处理 "\n" 和 .lower() 处理大小写:

Use rstrip() to deal with "\n" and .lower() to deal with case:

if what_to_draw == "flower/n":

elif(): 需要某种条件，否则使用 else:

elif(): requires a condition of some sort otherwise use else:

让我们尝试不同的方法.不要将控制台窗口输入与海龟图形混合在一起，让我们尝试使用 Python 3 海龟新增的 textinput() 函数从海龟内部执行所有操作:

Let's try a different approach. Instead of mixing console window input with turtle graphics, let's try to do everything from within turtle using the textinput() function that's new with Python 3 turtle:

from turtle import Turtle, Screen

def what_to_draw():
    title = "Make a sketch."

    while True:
        to_draw = screen.textinput(title, "What do you want to see?")

        if to_draw is None:  # user hit Cancel so quit
            break

        to_draw = to_draw.strip().lower()  # clean up input

        if to_draw == "flower":
            tortoise.forward(90)  # draw a flower here
            break
        elif to_draw == "frog":
            tortoise.backward(90)  # draw a frog here
            break
        else:
            title = to_draw.capitalize() + " isn't in the code."

tortoise = Turtle()

screen = Screen()

what_to_draw()

screen.mainloop()

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