如何在不提供搜索查询的情况下返回所有推文 [英] how to return all tweets without providing a search query

问题描述

我正在从事一个文本挖掘项目，用于分析推文.

I am working on a text mining project that deals with analyzing tweets.

我希望在短时间内(不超过一天)以英语发布所有推文，而不会使结果与特定的搜索查询、趋势或用户条件匹配.

I would like to get all tweets tweeted in english during a short period of time(not more than a day), without having the result matching to a specific search query, trend, or user criteria.

熟悉tweepy的api.search函数.但是，当我尝试在没有搜索查询的情况下运行它时:

I am familiar with tweepy's api.search function. However, when i try to run it without a search query:

api.search(count=remaining_tweets, since_id=str(since_id),lang='en', max_id=str(max_id-1))

我收到以下消息:出现异常，等待 15 分钟".

i get the following message: "exception raised, waiting 15 minutes".

推荐答案

您可以通过将 * 赋予查询参数来获取所有推文:

You can get all the tweet by giving * to the query parameter:

tweets = api.search(q='*', lang='en', count=200, since_id=since_id, max_id=max_id)

如果您需要特定数量的推文，您可以像这样使用 tweepy Cursor:

If you need a specific number of tweets, you could use tweepy Cursor like this:

# Get 1000 English tweets from max_id
tweets = [tweet for tweet in tweepy.Cursor(
    api.search, q='*', lang='en', count=200, max_id=max_id).items(1000)]

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